Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
1 answer:
Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:
The amount of salt needed for the calculated amount of seawater is:
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Answer:
Hydochloric acid
HCl
Explanation:
Hydrochloric acid is an acid and ionizes to form hydrogen and chloride ions.
The name of the compound that gives hydrogen ion and chloride ions in the solution state is Hydrochloric acid.
Hydrochloric acid is made up of one atom of hydrogen and 1 atom of chlorine. We can also say, it is made up of 1 mole of hydrogen and 1 mole of chlorine.
The formula of this compound is HCl;
In solution:
HCl → H⁺ + Cl⁻