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3 years ago

Which tools would be necessary to determine whether or not a large regular block will float, without using water?

2 answers:

6 0

Scale and measuring tape.
To determine the mass and volume, you can find the density. The block will float if its density is less than that of water.

zalisa [80]3 years ago

4 0

Answer:

Explanation:

To determine if the bock will float you need:

A scale to calcualte the weight of the block
A ruler or metric tape to measure the block and calculate its volume

The block has 3 dimmentions: lenght, wide and height, its volume is:

$V=wide*lenght*height$

Once calculated it and measured the weight, you calculate the density:

$\rho=\frac{m}{V}$

If the density of the block is smaller than the density of water (arroung 1000 kg/m3) the block will float.

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3 years ago

A student collects 25 mL of gas at 0.98 bar. What volume would this gas occupy at 1.013 bar? * 3 points 25.8 mL 24.2 mL .09 mL 3

trasher [3.6K]

Answer:

24.2 mL.

Explanation:

Assuming constant temperature, we can solve this problem using Boyle's law, which states:

P₁V₁=P₂V₂

Where:

P₁ = 0.98 bar

V₁ = 25 mL

P₂ = 1.013 bar

V₂ = ?

We input the data:

0.98 bar * 25 mL = 1.013 bar * V₂

And solve for V₂:

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3 0

3 years ago

How many moles of butane gas, C4H10, react to produce 2.50 moles of H2O? How many moles of oxygen gas reacts? Given the balanced

viva [34]

The moles of butane gas and oxygen gas reacted if 2.50 moles of H2O is produced is calculated as below

the equation for reaction
2C4H10 +13 O2 = 8CO2 +10 H2O

the moles of butane (C4H10) reacted calculation

by use of mole ratio between C4H10: H2O which is 2 : 10 the moles of C4H10= 2.50 x2/10 = 0.5 moles of C4H10 reacted

The moles of O2 reacted calculation

by use of mole ratio between O2 : H2O which is 13:10 the moles of O2

= 2.50 x 13/10= 3.25 moles of O2 reacted

5 0

3 years ago

The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combust

bearhunter [10]

The answer is 9.94 ml.

<h3>What is density?</h3>

Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.

Given,

The density of ethanol, C2H5OH = 0.789 g/mL

$n (CO_{2} ) = \frac{m}{M} = \frac{15G}{44 g/mol} } = 0.341 mol;$

$n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2} = \frac{0.341}{2} = 0.1705 mol;$

$m (C_{2} H_{2} OH) = 0.1705 mol * 46 g/ mol$ = 7.843 g

$V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.$

Therefore, the answer is 9.94 ml

Learn more about density of ethanol,

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The complete question is -

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

5 0

2 years ago