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3 years ago

13

2. IQ tests are usually designed so that the scores are normally distributed with mean 100 and standard

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

Ineedpoints inners pinotsinnned points songsdh

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How many solutions does 9x - 18 = 3(3x - 6) have?

lys-0071 [83]

Answer:

assuming the three options are no solutions, one solution and all real numbers, i would say the final option. i forgot what the proper wording is thoough

7 0

3 years ago

Read 2 more answers

Your grades on three exams are 80, 93, and 91. What grade do you need on the next exam to have an average of 90 on the four exam

Pani-rosa [81]

<u>Answer:</u>

96

<u>Step-by-step explanation:</u>

Let's assume that the marks needed in the next exam is $x$ . Then if the average becomes 90,

$\frac{80 + 93 + 91 + x}{4}= 90$

Now we can simply solve for $x$ :

⇒ $\frac{264 + x}{4}= 90$

⇒ $264 + x = 360$ [Multiplying both sides by 4]

⇒ $x = 360 - 264$ [Subtracting 264 from both sides]

⇒ $x = \bf96$

Therefore, you need to score 96 in your next exam to have an average of 90 on the four exams.

8 0

2 years ago

A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8

uysha [10]

Answer:

12

Step-by-step explanation:

Given :

Male Female Total

Registered 60

Non registered 40

Total 20 80

Solution :

N= 100

Formula of expected frequency = $E_{ij}=\frac{T_i \times T_j}{N}$

$E_{ij}$ = expected frequency for the ith row/jth columm.

$T_i$ = total in the ith row

$T_j$ = total in the jth column

N = table grand total.

So, using formula $E_{11}=\frac{T_1 \times T_1}{100}$

$E_{11}=\frac{60 \times 20}{100}$

$E_{11}=12$

$E_{12}=\frac{T_1 \times T_2}{100}$

$E_{12}=\frac{60 \times 80}{100}$

$E_{12}=48$

$E_{21}=\frac{T_2 \times T_1}{100}$

$E_{21}=\frac{40 \times 20}{100}$

$E_{21}=8$

$E_{22}=\frac{T_2 \times T_2}{100}$

$E_{22]=\frac{80 \times 40}{100}$

$E_{22}=32$

Expected frequency table

Male Female Total

Registered 12 48 60

Non registered 8 32 40

Total 20 80

So, the expected frequency for males who are registered voters are $E_{11}=12$

5 0

3 years ago

makvit [3.9K]

A hope this helps :)

3 0

3 years ago

Help me !!!!!!!!!!!!!!!!!!!!

True [87]

Answer:

0 isnt a number loll

Step-by-step explanation:

B

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3 years ago