The sides of the triangle are 20 in, 48 in and 52 in
<u>Explanation:</u>
Given:
Let x be the length of smaller leg
Hypotenuse, H = x + 32
Height, h = x + 28
Length of the sides of a triangle = ?
If the triangle is a right angle triangle then we use pythagoras theorm to solve the question.
So,
(Hypotenuse)² = (height)² + (Base)²
(x + 32)² = (x + 28)² + (x)²
x² + 1024 + 64x = x² + 784 + 56x + x²
240 + 8x - x² = 0
x² - 8x - 240 = 0
Solving the quadratic equation:
x² + 12x - 20x - 240 = 0
x(x+12) - 20(x+12) = 0
(x-20) (x+12) = 0
(x-20) = 0
x = 20 in
Hypotenuse, H = x + 32
H = 20 + 32 in
H = 52 in
Height, h = x + 28
h = 20 + 28 in
h = 48 in
Therefore, the sides of the triangle are 20 in, 48 in and 52 in
Answer= 42
Explanation: 7*6=42 42+6=48
Assuming you mean 90 students and not 90% its 27 got an A
Answer:
g(x) = 4(x + 7)
Step-by-step explanation:
i had this on a test i just took so it told me it was right bit if it is not i am sorry and i will recheck
30 60 90 right triangle
so
ratio of short leg : long leg : hypo = a : a√3 : 2a
if short leg = 10
long leg = 10√3 and hypo = 2 x 10 = 20
so a = 10√3, c + d = 20
also small triangle on right is 30 60 90 right triangle
hypo = 10, short leg d = 5 and long leg b = 5√3
if d = 5 then c = 20 - 5 = 15
answer
a = 10√3
b = 5√3
c = 15
d = 5