Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
Answer:
3 divided by 10
Step-by-step explanation:
D is equivalent because brackets don’t change anything here
Answer:
82 inches
Step-by-step explanation:
The difference between consecutive even integers is 2, thus
let the legs be n and n + 2
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
n² + (n + 2)² = 58² ← expand and simplify left side
n² + n² + 4n + 4 = 3364 ( subtract 3364 from both sides )
2n² + 4n - 3360 = 0 ( divide all terms by 2 )
n² + 2n - 1680 = 0 ← in standard form
(n + 42)(n - 40) = 0 ← in factored form
Equate each factor to zero and solve for n
n + 42 = 0 ⇒ n = - 42
n - 40 = 0 ⇒ n = 40
But n > 0 ⇒ n = 40
and n + 2 = 40 + 2 = 42
Thus sum of legs = 40 + 42 = 82 inches