Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given: = 2.0 M, = ?
= 0.5 M, = 500 mL
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that there is 125 mL of a 2.0 M solution are needed to make 500 mL of a 0.5 M solution.
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Hydrogen is grouped with the alkali metals because they are grouped based on their properties and behavior, and like the other elements in Group 1 (1A), it only has one valence.
15.5% by mass is
equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>
<span>we know that molality = moles solute / kg solvent
<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea
</span></span></span>
Since there are 155 g
urea in 1000g solution, hence the solvent is 845 g or 0.845 kg
So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>