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Serga [27]
3 years ago
5

Determine the molality of an aqueous solution that is 15.5 percent urea by mass.

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

15.5% by mass is equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>

<span>we know that molality = moles solute / kg solvent

<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea

</span></span></span>

Since there are 155 g urea in 1000g solution, hence the solvent is 845 g or 0.845 kg

So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>

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Explanation:

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1000 mL = 1 L

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