1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serga [27]
3 years ago
5

Determine the molality of an aqueous solution that is 15.5 percent urea by mass.

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

15.5% by mass is equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>

<span>we know that molality = moles solute / kg solvent

<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea

</span></span></span>

Since there are 155 g urea in 1000g solution, hence the solvent is 845 g or 0.845 kg

So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>

You might be interested in
4. The device shown is a
densk [106]

Answer:

The device shown is a calorimeter that used to measure the heat transfer by a reaction under constant volume.

Explanation:

8 0
3 years ago
Can somebody plz just answer this 1 question thx!!!
coldgirl [10]

Answer:

cetacean i think thats the answer

3 0
3 years ago
Given the following balanced reaction: 2 NH3 +CO2 --&gt; CH4N2O + H2O A reaction produces 87.5g of CH4N2O upon the reaction of 6
tankabanditka [31]

Answer:

ml lang yan pre tara laro

5 0
3 years ago
hich of the followings decrease the affinity of adult Hb with O2? A. 2,3 BPG B. hydrogen ion C. CO2 D. Ferrous ion
Ivahew [28]

Answer:

A. 2,3 BPG

Explanation:

2,3-bisphosphoglycerate (BPG), otherwise known as 2,3-DPG, enables the transition of hemoglobin from a very high-oxygen-affinity state to a reduced-oxygen-affinity state.

Tissues hemoglobin oxygen affinity is reduced by numerous physiological factors including.

1. Temperature Increased,

2. Carbon dioxide,

3. Acid and

4. 2,3-Bisphosphoglycerate (2,3-BPG)

all of which can contribute to decrease the oxygen affinity of hemoglobin which favours unloading and increased oxygen availability to our body cells.

3 0
3 years ago
Identify the molecule that effuses the fastest ch4 co ar or co2
Ksju [112]
<span>CH4 will effuse the fastest. The speed of effusion is proportional to the speed of the gas molecules with faster molecules effusing fast than slower molecules. And the speed of the molecules at any given temperature is inversely related to the mass of the molecules with lighter molecules being faster. So let's take a look at the mass of the candidate molecules and see which is lighter and therefore faster. CH4 - Molar mass is about 16. CO - Molar mass is about 28 Ar - Molar mass is about 40 CO2 - Molar mass is about 44 If the 4 options, CH4 (methane) is by far the lightest, and therefore the fastest, so will effuse faster than the other 3 gasses.</span>
5 0
3 years ago
Read 2 more answers
Other questions:
  • El amoniaco y el fluor reaccionan para formar tetrafluoruro de dinitrogeno y fluoruro de hidrogeno. segun la reaccion: NH3 + F2
    12·1 answer
  • Which measurement, temperature or volume, limits the precision of the data obtained in the experiment? explain?
    7·1 answer
  • Which statement describes an extensive property of matter?
    10·2 answers
  • When do you stop writing your electron configurations?
    10·1 answer
  • Which concern is the LEAST important when using a compound light microscope to view a sample of paramecia? A) obtaining good res
    10·2 answers
  • What are the most chemically stable elements (in terms of reactivity) on the periodic table?
    10·1 answer
  • BTW IT IS SCIENCE
    12·2 answers
  • A student mixed a small amount of iron filings and sulphur powder in a dish. He could not
    15·1 answer
  • If you have 250 mL of 0.75 M LINO2.<br> How many grams of this substance<br> would you have?
    15·1 answer
  • A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor h
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!