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3 years ago

What was one idea Dalton taught about atoms?

Chemistry

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Explanation:

All atoms of one type were identical in mass and properties.

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How many moles of copper are there in 6.93 g of copper sample<br>pls be quick

Alex_Xolod [135]

Molar mass of copper=63.5g/mol
Given mass=6.93g

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}$

$\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles$

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2 years ago

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What statement about gases is true?

kenny6666 [7]

Anything that is true

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3 years ago

If an effusion experiment, it required 45 seconds for

patriot [66]

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3 years ago

How much heat must be transferred to 55 g of ice to change the ice's temperature from -13°C to -5.0°C? (The specific heat capaci

notka56 [123]

Answer:

Hey i don't know if you still need the answer but this is what i think it is:

Explanation:

B is correct answer

15 j

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3 years ago

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Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.

sergejj [24]

The molecular formula of compound is $Al(C_{2}H_{3}O_{2})_{3}$ .

Since, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6.023\times 10^{23}$ atoms of $Al(C_{2}H_{3}O_{2})_{3}$ .

Thus, according to molecular formula, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6\times 6.023\times 10^{23}=3.61\times 10^{24}$ atoms of oxygen atoms.

1 atom of oxygen will be present in $\frac{1}{3.61\times 10^{24}}$ moles of $Al(C_{2}H_{3}O_{2})_{3}$ . Thus,

$2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}$ .

Molar mass of $Al(C_{2}H_{3}O_{2})_{3}$ is 236 g/mol, mass can be calculated as follows:

$m=n\times M=0.7285 mol\times 236 g/mol=172 g$

Therefore, mass of $Al(C_{2}H_{3}O_{2})_{3}$ will be 172 g.

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3 years ago

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