Nuclear reactions Alpha reactions
Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
How does hydrogen peroxide bleach hair? THe h202 molecule sbreak the double bonds in pigment molecules
Question 3
What advantage does hydrogen peroxide have over other bleaching agents such as chlorine gas? Hydrogen peroxide decomposes into nontoxic water and oxygen.
Question 4
How does hydrogen peroxide play a role in air pollution?Peroxide fragments react with unburned fuel creating eye irritants.
Question 5
In the reaction between melanin and hydrogen peroxide, which substance is oxidized (receives electrons)? melanin is oxidized,hydrogen peroxide is reduced
I assume there is a typo in the equation. It is H2O instead of H2I.
The ratio of H2 and O2 that react with each other is 2:1. To find out the grams of H2, we need to first find out the moles of O2 and H2.
Moles of O2 = mass of O2/molar mass of O2 = 192g/32g/mol = 6 mol. Therefore, the moles of H2 = 6mol *2 = 12 mol.
So the mass of H2 that reacts with O2 = moles of H2 * molar mass of H2 = 12 mol * 2 g/mol = 24 g
Answer: 100kPa
Explanation:
P1 = 3.00 x 10² kPa , P2 =?
T1 = 30°C = 30 +273 = 303k
T2 = —172°C = —172 + 273 = 101k
P1/T1 = P2/T2
3 x 10² / 303 = P2 / 101
P2 = (3 x 10² / 303) x 101
P2 = 100kPa
