Question

How many grams of steam at 100 °C would be required to raise the temperature

Answer 1

The mass of steam required to raise the temperature of water is 3.5 g.

The given parameters;

• mass of the benzene, = 47.6
• initial temperature of the benzene, = 5.5 ⁰C
• final temperature of the benzene = 30 ⁰C

The molar mass of Benzene = 78.11 g/mol

The molar mass of water = 18 g/mol

The number of moles of the Benzene is calculated as follows;

$n = \frac{47.6}{78.11} = 0.61 \ mole$

The mass of steam required is calculated as follows;

heat lost by steam = heat absorbed by benzene

$\frac{m}{18} \times 40.7 \times 10^3 = 47.6(1.63)(30-5.5) \ + \ 0.61 \times 9.87 \times 10^3\\\\2261.11 m = 7921.61\\\\m = \frac{7921.61}{2261.11} \\\\m = 3.5 \ g$

Thus, the mass of steam required to raise the temperature of water is 3.5 g.

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