The kinetic energy of the ball b is 12.3kJ and ball B to a is 14.2kj
Answer:
Mass = 0.008 g
Explanation:
Given data:
Volume of H₂ = 107 mL
Pressure = 104.8 KPa
Temperature = 30°C
Mass of H₂ present = ?
Solution:
Formula:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the units of temperature, pressure and volume.
Temperature = 30+273 = 303 K
Volume of H₂ = 107 mL (107/1000= 0.107 L)
Pressure = 104.8 KPa (104.8/101 = 1.04 atm)
by putting values,
1.04 atm ×0.107 L = n× 0.0821 atm.L/ mol.K × 303 K
0.11 atm.L = n×24.87 atm.L/ mol
n = 0.11 atm.L / 24.87 atm.L/ mol
n = 0.004
Mass of H₂:
Mass = number of moles × molar mass
Mass = 0.004 mol × 2 g/mol
Mass = 0.008 g
Balanced chemical reaction: 2KClO₃ → 2KCl + 3O₂.
Potassium is metal from first group of Periodic table of elements, it has always oxidation number in compound +1.
Chlorine in the reactant state has oxidation number +5 (+1 + x + 3 · (-2) = 0) and it is reduced to -1 (+1 + x = 0) in <span>the product state.
</span>Oxygen in the reactant state has oxidation number -2 (+1 + 5 + 3 · x = 0) and it is oxidized to 0 (in molecule of oxygen) in the product state.
2.3 M is the molarity of a solution that contains 2.3 moles of solute in 1.0 liter of solution.
Explanation:
Data given:
volume of the solution = 1 litre
number of moles of the solute = 2.3 moles
Molarity of a solution is given by number of moles of a given solute in a given volume in litres.
The unit of molarity = moles/litre
The formula used to calculate molarity is given by:
molarity =
Putting the values in the equation,
molarity =
molarity = 2.3
Thus the molarity of the given solution is 2.3 moles/litre.
The molarity of the solution is also written as 2.3 M.
Answer:
Explanation:
Gilman reagent is also known as the Lithium organocuprates. They are used as nucleophiles in the organic synthesis.
Gilman reagent is used for C - C bond formation.
H H H
| | |
-----→ H - C -- C -- C -- C =
(1 bromo propane) | | | |
H H H H
(1 pentene)
Normally in C--C formation by Gilman reagent, the following reactions takes place :
R -- Br + R--R' + R' Cu + Li Br
In 1 pentene, i.e.
(from 1 bromo (from Gilman reagent)
propane)
So Gilman reagent is
Organo lithium compound is