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ArbitrLikvidat [17]
3 years ago
13

Suppose that in a particular reaction 10.5 grams of HCl (36.5 g/mol) react with excess NaOH and 19.3 grams of NaCl (58.5 g/mol)

are isolated from the reaction mixture by crystallization. What is the percent yield of NaCl in the experiement?
Chemistry
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

The answer to your question is 114.7% the percent is higher than expected.

Explanation:

Data

mass of HCl = 10.5 g

molar mass of HCl = 36.5 g

mass of NaOH = 19.3 g

molar mass of NaOH = 58.5

Process

1.- Write the balanced chemical reaction

                    HCl  +   NaOH   ⇒    NaCl  +  H₂O

2.- Calculate the theoretical yield

                    36.5 g of HCl -------------- 58.5 g of NaCl

                     10.5 g of HCl --------------  x

                     x = (10.5 x 58.5)/36.5

                     x = 16.83 g

3.- Calculate the percent yield

                     % yield = (19.3/16.83) x 100

                     % yield = 114.7

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The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

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