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juin [17]
3 years ago
15

What figure is comprised of two rays that share a common end point called a vertex

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0
Angle is compromised of two rays that share a common endpoint called a vertex.
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10x-4y=8<br> 3x - 4y = -6. What’s the x and y
Alik [6]
X equals 2 and Y equals 3.
10(2)-4(3)= 20-12. Which is 8.
3(2)-4(3)=6-12. Which equals -6.
Please vote my answer brainliest! Thanks.
6 0
4 years ago
If angle A B C is congruent to angle C B D find x.
madam [21]
X+1=4x-2
  +2      +2
x+3=4x
-x     -x
3=3x
1=x

4 0
3 years ago
Jayden pays a $100 installation fee and a $30 monthly service for his
Elza [17]
Y = 30x + 100 i think
8 0
3 years ago
Please help please and thank you
Katyanochek1 [597]

Step-by-step explanation:

\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta

3 0
3 years ago
The drama club was selling ticketsto the school play. Adult ticketscost $8.00 each, and studenttickets cost $5.00 each. The litt
BlackZzzverrR [31]

We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

A+S=284,(1)

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

8A+5S=1948,(2)

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

\begin{gathered} A+S-S=284-S \\ A=284-S \end{gathered}

Now we will replace this value in equation (2):

8(284-S)+5S=1948

Now we will apply the distributive property:

2272-8S+5S=1948

Addins like terms:

2272-3S=1948

Subtracting 2272 to both sides;

\begin{gathered} 2272-2272-3S=1948-2272 \\ -3S=-324 \end{gathered}

Dividing both sides by -3:

S=-\frac{324}{-3}=108

Now we replace this value in equation (1), where we have already solved for A:

\begin{gathered} A=248-108 \\ A=140 \end{gathered}

Therefore, there were sold 108 student tickets and 140 adult tickets.

3 0
1 year ago
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