The Hall-He'oult process is expensive and consumes large amounts of
energy to produce Aluminum.
The answer is a throw the ball with greater force
The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.
The balanced chemical reaction is :
<em> 2Na + Cl₂ → 2NaCl</em>
<em />
Given data :
Mass of sodium = 10.0 g
Number of moles of Na -
Number of moles = <u> Given mass </u>
Molar mass
Number of moles = <u> 10.0 g</u> = 0.43 mol
23 g
Comparing moles of Na and Cl₂ from the balanced chemical equation,
Na : Cl₂
2 : 1
0.43 : <u> 1 </u> x 0.43 = 0.215 mol
2
Mass of chlorine gas :
(molar mass of chlorine = 71 g)
Mass of chlorine = number of moles x molar mass
Mass = 0.215 mol x 71 g/mol
= 15.26 g
To learn more about sodium and chlorine,
brainly.com/question/14588368
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