All categories

3 years ago

What type of energy travels in the form of electromagnetic waves?

Chemistry

1 answer:

almond37 [142]3 years ago

3 0

Light/thermal. Charges move back and forth which move at the speed of light

You might be interested in

How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?

allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

volume Na2S = 0.0212 L = 21.2 mL

6 0

3 years ago

Which type of front does not move

shusha [124]

Stationary Front: a front that is not moving. When a warm or cold front stops moving, it becomes a stationary front.

5 0

3 years ago

Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.

Anvisha [2.4K]

Answer : The rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : $2NO+H_2\rightarrow N_2+H_2O_2$ (slow)

Step 2 : $H_2O_2+H_2\rightarrow 2H_2O$ (fast)

Overall reaction : $2NO+2H_2\rightarrow N_2+2H_2O$

The rate law expression for overall reaction should be in terms of $NO\text{ and }H_2$ .

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$2NO+H_2\rightarrow N_2+H_2O_2$

The expression of rate law for this reaction will be,

$Rate=k[NO]^2[H_2]$

Hence, the rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

8 0

4 years ago

4. Balance the following chemical equation. Say what the coefficients "a"

lisabon 2012 [21]

Answer:

a = 4

b = 3

Explanation:

SOLUTION :-

Balance it by using 'hit & trial' method , and you'll get the answer :-

2Fe₂O + 3C → 4Fe + 3CO₂

⇒ a = 4 ; b = 3

VERIFICATION :-

In reactant side of equation :-

Number of atoms in Fe = 2×2 = 4
Number of atoms in O = 2×3 = 6
Number of atoms in C = 3×1 = 3

In product side of equation :-

Number of atoms in Fe = 4×1 = 4
Number of atoms in C = 3×1 = 3
Number of atoms in O = 3×2 = 6

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

6 0

3 years ago

A chemist describes a particular experiment in this way: "0.0400 mol of H2O2 decomposed into 0.0400 mol of H2O and 0.0200 mol o

AleksandrR [38]

Description:

"0.0400 mol of H2O2 decomposed into 0.0400 mol of H2O and 0.0200 mol of O2."

This means that a certain amount of H2O2 (0.0400 mol) decomposed or was broken down into two components, 0.04 mol of H2O and 0.02 mol of O2. To examine the system, we need a balanced equation:

H2O2 ---> H2O + 0.5O2

The final concentrations of the system indicates that the system is in equilibrium.

4 0

3 years ago