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2 years ago

Find the 12th term of the geometric sequence -2,4,-8..

Mathematics

1 answer:

WINSTONCH [101]2 years ago

3 0

Answer:

-16394

Step-by-step explanation:

Pattern rule : Start at -2 and multiply it by -2.

-2 x -2 = 4

4 x -2 = -8

-8 x -2 = 16

16 x -2 = -32

- 32 x -2 = 64...so on

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marissa [1.9K]

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Step-by-step explanation:

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2 years ago

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Find the midpoint of the segment with the following endpoints. (10, 7) and (5, 4)

KatRina [158]

Answer:

$\frac{15}{2} , \frac{11}{2}$

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

$\frac{x1 +x2}{2} , \frac{y1 + y2}{2}$

x1 = 10

x2 = 5

y1 = 7

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2 years ago

The equation y+6=1/3(x-9) is written in point-slope form. What is the equation written in slope-intercept form?

Margaret [11]

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Moved all terms from left to right that doesn't contain y

Y=-6 +1/3x-3

Simplify

Y=1/3x-9

Your answer is c.

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3 years ago

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3 years ago

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Find the exact length of the midsegment of the trapezoid with the vertices S(−2, 4), T(−2,−4), U(3,−2), V(13, 10).

Vlada [557]

Check the picture below.

first off we'll need to know the midpoints of ST and UV, well, from ST as you can see in the picture, is just a vertical line, so its midpoint is simply (-2,0), let's find it for UV

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ U(\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad V(\stackrel{x_2}{13}~,~\stackrel{y_2}{10}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{13+3}{2}~~,~~\cfrac{10-2}{2} \right)\implies \left( \cfrac{16}{2}~~,~~\cfrac{8}{2} \right)\implies (8~~,~~4) \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[8-(-2)]^2+[4-0]^2}\implies d=\sqrt{(8+2)^2+(4-0)^2} \\\\\\ d=\sqrt{10^2+4^2}\implies d=\sqrt{116}\implies d\approx 10.77$

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2 years ago