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3 years ago

How many five digit ZIP Codes are possible if the two numbers cannot be zero or a one? (Numbers can repeat)

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

5 0

Answer:

This means 100000 possible zip codes if repeatable

Step-by-step explanation:

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3 years ago

If f(x) = 7+ 4x and g(x) = 1/2,

olchik [2.2K]

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<h3>Further explanation</h3>

<u>Given:</u>

$\boxed{ \ f(x) = 7 + 4x \ }$
$\boxed{ \ g(x) = \frac{1}{2x} \ }$

<u>Question:</u>

What is the value of $\boxed{ \ \bigg( \frac{f}{g} \bigg)(5)? \ }$

<u>The Process:</u>

The form of $\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ }$ means that f(x) is divided by g(x).

$\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ } \rightarrow \boxed{ \ \frac{f(x)}{g(x)} \ }}$

Let us solve the problem.

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = \frac{7 + 4x}{\frac{1}{2x}} \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = (7 + 4x) \times \frac{2x}{1} \ }$

Thus, we get $\boxed{{ \ \bigg( \frac{f}{g} \bigg)(x) = 14x + 8x^2 \ }}$

And now, we can calculate the value of $\bigg( \frac{f}{g} \bigg)(5)$ .

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 14(5) + 8(5)^2 \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 70 + 200 \ }$

Thus, the value is 270.

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Alternative thinking

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = \frac{7 + 4(5)}{\frac{1}{2(5)}} \ }$

$\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = (7 + 20) \times 10} \ }$

$\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 270 \ }}$

<h3>Learn more</h3>

If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
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If g(x) is the inverse of f(x), what is the value of f(g(2)) brainly.com/question/1517760

Keywords: if, f(x), g(x), function, divide by, the value, (f/g)(5), 5, 270

#learnwithBrainly

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3 years ago

How many five digit ZIP Codes are possible if the two numbers cannot be zero or a one￼? (Numbers can repeat)

How many five digit ZIP Codes are possible if the two numbers cannot be zero or a one? (Numbers can repeat)