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3 years ago

14

If you lived on Saturn, which planets would exhibit retrograde motion like that observed for Mars from Earth? (Select all that a

pply.)
Mercury
Venus
Earth
Mars
Jupiter
Uranus
Neptune

2 answers:

slavikrds [6]3 years ago

7 0

Mars , Jupiter , Neptune

DochEvi [55]3 years ago

5 0

Answer:

earth , mercury , and neptune

Explanation:

pls mark brainless

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As you slide a heavy box across the floor, friction applies a force of -100 N

nirvana33 [79]

Answer:

A -500J

Explanation:

because W=Fs

100 × 5 = 500

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g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the

MrRa [10]

Answer:

Approximately $-1.58\; \rm rad \cdot s^{-2}$ .

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

$v^2 - u^2 = 2\, a\, x$ ,

where

$v$ is the final velocity of the moving object,
$u$ is the initial velocity of the moving object,
$a$ is the (linear) acceleration of the moving object, and
$x$ is the (linear) displacement of the object while its velocity changed from $u$ to $v$ .

The angular analogue of that equation will be:

$(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ , where

$\omega(\text{final})$ and $\omega(\text{initial})$ are the initial and final angular velocity of the rotating object,
$\alpha$ is the angular acceleration of the moving object, and
$\theta$ is the angular displacement of the object while its angular velocity changed from $\omega(\text{initial})$ to $\omega(\text{final})$ .

For this object:

$\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}$ , whereas
$\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}$ .

The question is asking for an angular acceleration with the unit $\rm rad \cdot s^{-1}$ . However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

$\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}$ .

Rearrange the equation $(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ and solve for $\alpha$ :

$\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}$ .

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3 years ago

A dog walks along The ground. If the dog applies an action force on the ground, what is the reaction force?

fiasKO [112]

Explanation:

Action and reaction are two forces that are equal in magnitude but the direction is opposite.

When a dog walks along the ground, the action force is the force that dog applies on the ground. On the other hand, the reaction force is the force that the ground applies on the dog. It is based on Newton's third law of motion.

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Frosty the Snowman accelerates from 16 m/s to 26 m/s in 2 s. What is his acceleration?

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Answer:

his acceleration is 3.25

Explanation:

because you do 26÷16 which =1.625×2=3.25

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densk [106]

The answer is A

Theory- a hypothesis or an educated guess that has yet to be proven by experiment<span />

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