Florida. The beaches are great
Answer:
The charge on the ball bearing 4.507 × 10^-8 C
Explanation:
From Coulomb's law
F = kq1q2/r²
make q2 the subject
q2 = Fr²/kq1
q2 = (1.8×10^-2 × 0.026²) ÷ (9×10^9 × 30×10^-9)
q2 = 4.507 × 10^-8 C
Linear momentum is conserved, so the speed of the block after
the bullet has passed through it and continued on its way is
(383 · mass of the bullet) divided by (mass of the block)