Answer:
1.4 * 10 ^-1 Ω
Explanation:
Hi,
For this question, we gotta use the formula
R = pL/A
p = The resistivity of your material at 20°C
L = length of the wire
A = cross-sectional area
The resistivity of tungsten is 5.60 * 10^-8 at 20°C
By plugging the values, we get:
R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω
Answer:
The answer to A strip of copper metal is placed in an aqueous sodium chloride solution. According to the standard reduction potential below, is Option A) No reaction occurs
Explanation:
Aqueous sodium chloride solution is similar to salt and water mixed together.
Copper doesn’t dissolve in salty water. However, exposure of the metal to air and then to water results in an oxide layer on the surface of copper which is referred: the dull reddish brown copper(I) oxide and this exists in an equilibrium with the outer oxide layer of black copper(II) oxide.
If you put a strip of copper metal is placed in an aqueous sodium chloride solution, you will not observe any reaction because the oxide layer on the surface of copper is too thin for to be noticed other than by a dulling or darkening of the surface, not thick enough to be obvious.
Answer:
5.1m
Explanation:
Given the following parameters
Speed v = 10m/s
Time = 3.0s
Required
Displacement of the tennis ball
Using the equation of motion
v² =u²-2gh (g i s negative due to upward motion of the ball)
Substitute the given values into the expression above;
0² = 10²-2(9.8)h
0 = 100-19.6h
19.6h = 100
h = 100/19.6
h= 5.1m
Hence the displacement of the ball is 5.1m
You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object
The work done to push the box is equal to the product between the force and the distance through which the force is applied:
In our problem, the force is F=1.4 N and the distance covered is d=150 m, so the work done by pushing the box is
