|acceleration| = (change in speed) / (time for the change)
Change in the car's speed = (27 - 0) = 27 m/s
Time for the change = 10 sec
|acceleration| = (27 m/s) / (10 s) = 2.7 m/s² .
That's the magnitude of the car's acceleration.
We don't know anything about its direction.
Answer:
the mass of the air in the classroom = 2322 kg
Explanation:
given:
A classroom is about 3 meters high, 20 meters wide and 30 meters long.
If the density of air is 1.29 kg/m3
find:
what is the mass of the air in the classroom?
density = mass / volume
where mass (m) = 1.29 kg/m³
volume = 3m x 20m x 30m = 1800 m³
plugin values into the formula
1.29 kg/m³ = <u> mass </u>
1800 m³
mass = 1.29 kg/m³ ( 1800 m³ )
mass = 2322 kg
therefore,
the mass of the air in the classroom = 2322 kg
Answer:
-30°C
Explanation:
F-32/180 =C-0/100
or, -22-32/180=C/100
or, -54/180*100=C
or, -0.3*100=C
therefore, C= -30
-22°F = -30°C
PLEASE MARK ME AS BRAINLIEST!
Answer:
The formula for speed is speed=<u>d</u><u>i</u><u>s</u><u>t</u><u>a</u><u>n</u><u>c</u><u>e</u>
time
Explanation:
to work out what the units are for speed,you need to know the units for distance and time.In this example,distance is in metres(m) and time is in seconds (s) , so the units for speed is metre per second (m/s).
There are lots of variables that directly and indirectly contribute to the presence of gas on a surface
if the size of a planet is relatively small it will in turn be that of a smaller area which results in the less area to be covered for gas which basically means higher presence
I can go in depth more but I don't think that would be necessary all you need to know is this ...based on the size and gas will in turn be parallel to it's conformity
