PLA is a type of condensation polymer. Hydroxyl group of one lactic acid reacts with carboxylic group of second lactic acid and a ester is formed with the elimination of water molecule. And the reaction propagates with the increase in chain. And, the product formed is PLA as shown below.
Magnetic fields are created due to high levels of electricity
The two reasons Democritus’ ideas about the atom were NOT accepted are atoms are indestructible and they move in infinite space.
<h3>
What is atom?</h3>
An atom is the smallest unit of ordinary matter that forms a chemical element.
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Democritus’ ideas about atom</h3>
Democritus believed that atoms were uniform, solid, hard, incompressible, and indestructible and that they moved in infinite numbers through empty space until stopped.
Differences in atomic shape and size determined the various properties of matter.
Thus, the two reasons Democritus’ ideas about the atom were NOT accepted are atoms are indestructible and they move in infinite space.
Learn more about atoms here: brainly.com/question/6258301
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Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
Answer:
There are 6.024 grams of sodium hydroxide in the solution.
Explanation:
Moles of sodium hydroxide = n
Volume of sodium hydroxide solution = 251.0 mL = 0.251 L
Molarity of the sodium hydroxide = 0.600 M
Mass of 0.1506 moles of NaOH :
There are 6.024 grams of sodium hydroxide in the solution.
