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vladimir2022 [97]
3 years ago
9

A desert area has many species of cactus and brush as well as birds, snakes, lizards, and rodents. This desert is an example of

a
Chemistry
1 answer:
juin [17]3 years ago
3 0

Answer: Climax Commuity.

Explanation: (hope it’s right! Good luck!)

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Portal system. Think that may help
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Consider the following equilibrium between N2O4 and NO2.[Heat is added to a brown 2 NO2 gas to yield a colorless N2O4 gas]Which
LekaFEV [45]

Answer:

a.Low temperature

Explanation

Equation of reaction:

2NO2 <==> N2O4(g) ∆H = +ve

To cause the reaction to become darker brown means to produce more of NO2 gas. That is backward reaction.

Since the reaction is endothermic, decrease in temperature will shift the equilibrium position to the left thereby favouring backward reaction. This is in line with Me Chatelier's principle.

High pressure will rather favour forward reaction (it is not the right option).

7 0
3 years ago
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if a chemical reaction such as photosynthesis begins with 12 atoms of carbon how many atoms of carbon should be in the products
AveGali [126]

Answer:

12 atoms of course

Explanation:

5 0
3 years ago
Covert to scientific notation.
gtnhenbr [62]

Answer:

19) 3.6920 × 10⁻⁵

20) 4.059× 10²

21) 2.46810121416 × 10³

22)  1.0000× 10⁻³

Explanation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

For example:

0.000036920

In scientific notation =  3.6920 × 10⁻⁵

405.9

In scientific notation  = 4.059× 10²

2468.10121416

In scientific notation  = 2.46810121416 × 10³

0.0010000

In scientific notation  = 1.0000× 10⁻³

8 0
3 years ago
Answer the following questions about the solubility of AgCl(s). The value of Ksp for AgCl(s) is 1.8 × 10−10.
Firlakuza [10]

Answer:

  • [Ag⁺] = 1.3 × 10⁻⁵M
  • s = 3.3 × 10⁻¹⁰ M
  • Because the common ion effect.

Explanation:

<u></u>

<u>1. Value of [Ag⁺]  in a saturated solution of AgCl in distilled water.</u>

The value of [Ag⁺]  in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

The ICE (initial, change, equilibrium) table is:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

I            X                      0                    0

C          -s                      +s                  +s

E         X - s                   s                     s

Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.

Thus, the Ksp equation is:

  • Ksp = [Ag⁺] [Cl⁻]
  • Ksp = s × s
  • Ksp = s²

By substitution:

  • 1.8 × 10⁻¹⁰ = s²
  • s = 1.34 × 10⁻⁵M

Rounding to two significant figures:

  • [Ag⁺] = 1.3 × 10⁻⁵M ← answer

<u></u>

<u>2. Molar solubility of AgCl(s) in seawater</u>

Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.

The new ICE table will be:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

I            X                      0                  0.54

C          -s                      +s                  +s

E         X - s                   s                     s + 0.54

The new equation for the Ksp equation will be:

  • Ksp = [Ag⁺] [Cl⁻]
  • Ksp = s × ( s + 0.54)
  • Ksp = s² + 0.54s

By substitution:

  • 1.8 × 10⁻¹⁰ = s² + 0.54s
  • s² + 0.54s - 1.8 × 10⁻¹⁰ = 0

Now you must solve a quadratic equation.

Use the quadratic formula:

     

     s=\dfrac{-0.54\pm\sqrt{0.54^2-4(1)(-1.8\times 10^{-10})}}{2(1)}

The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer

<u>3. Why is AgCl(s) less soluble in seawater than in distilled water.</u>

AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.

This is known as the common ion effect.

By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.

In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.

3 0
3 years ago
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