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makkiz [27]
3 years ago
8

Which of these is the balanced equation for this reaction?

Chemistry
1 answer:
Georgia [21]3 years ago
5 0

Explanation:

This looks like a double-replacement reaction, and ALL YOU NEED TO DO is make sure that each element as the SAME AMOUNT on BOTH SIDES of the yield.

I am joyous to assist you anytime.

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An atomic radius is about 1.00*10^2 pm. Convert the radius to inches. (1 pm=10^-12m)
natka813 [3]

Answer:

3.937 x 10⁻⁸ inches

Explanation:

Data Given:

Atomic radium in pm (picometer) = 1.00 x 10² pm

Atomic radium in inches = ?

1 pm = 10⁻¹² m

Solution:

First convert picometer to meter

As we Know

  1 pm = 10⁻¹² m

then

  1.00 x 10² pm = X meter

Do cross multiplication

        X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm

       X meter = 1 x 10⁻⁹ m

So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m

Now convert meter to inches

As

         1 m = 39.37 inches

         1 x 10⁻⁹ m = X inches

Do cross multiplication

        X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m

        X inches = 3.937 x 10⁻⁸ inches

So,

1.00 x 10² pm = 3.937 x 10⁻⁸ inches

so the radius is 3.937 x 10⁻⁸ inches

4 0
3 years ago
The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai
Firdavs [7]

Answer:

A) N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g).

B) Kc=0.0933.

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

A)

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

B) For the calculation of Kc, we rate the equilibrium expression:

Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent x, we have:

[NH_3]=0.6M=2*x

x=\frac{0.6M}{2}=0.3M

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M

[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M

Therefore, the equilibrium constant is:

Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933

C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.

D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

Best regards.

7 0
3 years ago
What type of reaction is this?<br> 2Na(s) + Cl2(g) —&gt; 2NaCl(s)
soldier1979 [14.2K]

Answer: Synthesis

Explanation:

2 or more substances combine to form a new compound. In this case 2Na(s) combined with Cl2(g) to make 2NaCl(s)

A + X ---> AX

7 0
3 years ago
In a water molecule, two hydrogen atoms bind to one oxygen atom. How many lone pairs of electrons will be shown around each hydr
anzhelika [568]
There are no lone pair of electrons shown around the hydrogen atoms, rather there are 2 lone election pairs present around the central atom in this Lewis structure and that is Oxygen. Hydrogen only has bonding electrons, and it requires 2 electrons per hydrogen to achieve stability and have a full valence electron shell.
5 0
3 years ago
Read 2 more answers
Using the van der Waals equation, calculate the pressure for a 1.25 mol sample of xenon contained in a volume of 1.000L at 75°C
alina1380 [7]

Answer:

ABC

Explanation:

hrdjyt

5 0
2 years ago
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