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garik1379 [7]
3 years ago
8

A food processor draws 8.47 A of current when connected to a potential difference of 110 V.

Physics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

i want the answer

Explanation:i want the answer

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Identical forces act for the same length of time on two different masses. The change in momentum of the smaller mass is
xenn [34]

Answer:

Equal to change in momentum of larger mass.

Explanation:

We are given that

Two difference  masses .

Force act on both masses  for the same length of time.

We have to find the change in momentum of the smaller mass.

Let M and m are two masses

M>m

We know that

Change in momentum for large mass=F\Delta t

Change in momentum for small mass=F\Delta t

Because Force and length of time are same for both masses .

Hence, the change in momentum of smaller mass is equal to change in momentum of larger mass.

7 0
3 years ago
What is the weight in Newtons of a ball with a mass of 7.77 kg?
rusak2 [61]

Answer:

76.1N

Explanation:

Given parameters:

Mass of the ball  = 7.77kg

Unknow:

Weight of balloon  = ?

Solution:

Weight is the vertical force applied on a body.

  Weight = mass x acceleration due gravity

So;

  Weight  = mass x acceleration due to gravity

So;

 Weight  = 7.77 x 9.8  = 76.1N

4 0
3 years ago
A ball of mass m is thrown into the air in a 45° direction of the horizon, after 3 seconds the ball is seen in a direction 30° f
Rzqust [24]

Answer:

Velocity (magnitude) is 98.37 m/s

Explanation:

We use the vertical component of the initial velocity, which is:

v_{0y}=v_0*sin(45)=\frac{\sqrt{2} }{2}v_0

Using kinematics expression of vertical velocity (in y direction) for an accelerated motion (constant acceleration, which is gravity):

v_{y}=v_{0y}+a*t=\frac{\sqrt{2} }{2}v_0-9.8t

Now we need to find v_y as a function of v_0. We use the horizontal velocity, which is always the same as follow:

v_x=v_0cos(45\º)=\frac{\sqrt{2} }{2}v_0=v_{t=3}*cos(30\º) \\

We know the angle at 3 seconds:

v_y(t=3)=v_{t=3}*sin(30\º)\\v_{t=3}=\frac{v_y}{sin(30\º)}

Substitute  v_{t=3} in  v_x and then solve for  v_y

\frac{\sqrt{2} }{2}v_0=\frac{v_y*cos(30\º) }{sin(30\º)} \\v_y=\frac{\sqrt{6} }{6}v_0

With this expression we go back to the kinematic equation and solve it for initial speed

\frac{\sqrt{6} }{6} v_0 =\frac{\sqrt{2} }{2}v_0-29.4\\v_0(\frac{\sqrt{6}-3\sqrt{2}}{6} )=-29.4\\v_0=98.37 m/s

3 0
4 years ago
Two objects with a mass of 10,000-kg each and a distance of 1 meter between them.
Fofino [41]

Answer:

d) What is the force if we doubled both the masses AND we doubled the distance

4 0
3 years ago
Where are the oldest rocks found ?
nignag [31]

Answer:

zircons

Explanation:

they are over 4.375 billion years old

7 0
3 years ago
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