Since the velocity is constant, then the acceleration is zero over that time.
v2 = ?
m1 = 10kg
m2 = 70kg
v1 = 4m/s
E1 = E2
E1 = 1/2 * m1 * v1^2 = 1/2 * 10kg * 4m/s^2 = 80J
E2 = 1/2 * m2 * v2^2 = 80 J
v2 = √(E2/(2 * m2)) = √(80J/(2 * 70kg)) = about 0.76m/s
Answer:
The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.
Explanation:
I hope this helps a little bit.
2. random motion in vertical direction
Answer:
y (lambda) = c / f incident wavelength
y = 3 * E8 / 2.4 * E9 = .125 m incident wavelength
y' = .125 / 1.45 = .0862 m wavelength inside of tray
T = y' / 4 thickness required for phase change at bottom
T = .0862 m / 4 = .0261 m = 2.61 cm