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3 years ago

6

Suppose $P$ is the point $(5,3)$ and $Q$ is the point $(-3,6)$. Find point $T$ such that $Q$ is the midpoint of segment $\overli

ne{PT}$.
help qwikly

1 answer:

LekaFEV [45]3 years ago

5 0

Answer:

(1,4.5)

( $\frac{5+(-3)}{2} ,\frac{3+6}{2}$ )

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451 mi + 7.2 hr = ___ ___ (Round to the appropriate number of significant digits.)

gladu [14]

Answer:

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8 0

3 years ago

Find Y (pic attached) (i’ll mark brainliest)

Nadya [2.5K]

Answer:

4y - 4 = 60

4y = 64

Y = 16

Answer is B

I get 60 as it is a equilateral triangle.

Thank you and please rate me as brainliest as it will help me to level up

5 0

3 years ago

Points (−3, 5) and (3, 5) on the coordinate grid below show the positions of two players on a tennis court:

Anna35 [415]

Answer:

4. Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

Step-by-step explanation:

Player 1's position is (-3, 5).

It means that it is 3 units left from the origin and 5 units above the origin.

Player 2's position is (3, 5).

It means that it is 3 units right from the origin and 5 units above the origin.

Hence, the two points are on the same horizontal line bisected by the y-axis.

So, Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

3 0

3 years ago

Heidi and Andrew designed two raised flowerbeds for their garden. Heidi’s flower bed was 5 feet long by 3 feet wide, and Andrew’

Alona [7]

Answer:

90 ft³

Step-by-step explanation:

Volume is calculated as length × width × height.

Heidi: 5×3×2 = 30 ft³

Andres: 5×6×2 = 60 ft³

Total: 30 + 60 = 90 ft³

3 0

3 years ago

A STUDENT FINISHES THEIR FISR HALF OF AN EXAM IN 2/3 THE TIME IT TAKES HIM TO FINISH THE SECOND HALF. IF THE ENTIRE EXAM TAKES H

shepuryov [24]

Answer: First half was 24 minutes

Step-by-step explanation:

Let the time taken to finish the second half be y.

Since the student used 2/3 of the second half time to finish the first half, first half = 2/3 × y = 2y/3

The entire exam is an hour which equals 60 minutes

First half + Second half = 60minutes

Note that first half is denoted as 2y/3 and second half is denoted by y.

2y/3 + y = 60

5y/3 = 60

Cross multiply

5y = 60 × 3

5y = 180

y = 180/5

y = 36

Second half took 36 minutes

Since first half is 2y/3, it will be:

(2×36) / 3

= 72/3

= 24minutes

First half took 24 minutes.

8 0

3 years ago