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Suppose $P$ is the point $(5,3)$ and $Q$ is the point $(-3,6)$. Find point $T$ such that $Q$ is the midpoint of segment $\overli
1 answer:
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Answer:
JK= 3 in
Step-by-step explanation:
There is a theorem that says that the angle of a tangent and the radius is of 90°
so we can use the pythagora's theorem
Answer:
Option A. (-1, 0)
Step-by-step explanation:
In the figure attached,
Circle O is a unit circle (having radius r = 1 unit)
If a point A with central angles = θ, is lying on the circle then the coordinates of the point A will be,
x = r.cosθ
x = 1.cosθ = cosθ
and y = r.sinθ
y = 1.sinθ = sinθ
Therefore, coordinates representing the point A will be (cosθ, sinθ).
As per question the given point A is lying at P (a point having central angle θ = 180°)
Coordinates of point P will be
(x', y') → (cos180°, sin180°)
→ (-1, 0)
Therefore, Option A will be the answer.
