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solniwko [45]
2 years ago
7

Im totally NOT giving away points and this totally IS a real question so pls help (jkjk)

Mathematics
2 answers:
Sloan [31]2 years ago
7 0

Answer:

Super Hyper Ultra Ultimate Deluxe Perfect Amazing Shining God 東方不敗 Master Ginga Victory Strong Cute Beautiful Galaxy Baby 無限 無敵 無双 senchou here, thank you for the points :D

Step-by-step explanation:

Mashcka [7]2 years ago
6 0
Oh I totally understand alright

(Thanks hope you have a good day)
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QUICK WHATS THE ANSWER!!!!
Evgen [1.6K]

Answer:

It’s triangular prism

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
I want to know the answers to the ones circled
LenaWriter [7]

Hello! I will do my best to help you understand and receive the answers.

Let's begin with our first question..

15.) Dao has 2 3/8 pounds of hamburger meat. He is making 1/4 pound burgers. How many burgers can he make?

 For this problem we will have to use division. Our equation (use a calculator if needed) is 2 3/8  divided by 1/4  which equals 3.

Your final answer should be : Dao can make 3 hamburgers total.

I would answer the next question, but I believe from this information above you can try and figure it out. If you are still stuck, message  me and i can help you from there.


:))


4 0
3 years ago
Raise g to the 7th power, multiply the result by 4, then subtract f from what you have
WINSTONCH [101]

Answer:

f - 4(g^7)

It's simple algebraic operations!

7 0
2 years ago
Oliver and layla each built a rectangular prism with centimeter cubes. Both prisms have a volume of 24 cubic centimeters, but th
Nadusha1986 [10]
The volume of a rectangular prism is width×length×width. With the given volume of 24 you could find 2 ways with different sets of numbers that multiply into 24.

Oliver's= 6, 2, 2
Layla, 3, 2, 4
4 0
2 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
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