The z scores corresponding to the mean weight of a rotten apple relative to the apples from either orchard are, respectively,
The mean for the standard normal distribution is 0, which means that z scores closer to 0 represent data points that are more likely to occur. Therefore it's reasonable to believe that rotten apples occur more often in shipments from Zippy's.
(sec O - 1)(sec O - 2)
sec O = 1 , 2
O = 45 , 26.6 degrees These are the angles in first quadrant
Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.
The value of the land increases by 13.17% each year So it's growth function which is V (t)=15000 (1+r)^t Where r is the growth rate which is in decimal 13.17/100=0.1317
So it's
D) V(t) = 15000(1.1317)t; growth
