By titrating any acid against a standardized alkali solution, the perceived acidity of the substance is determined. It is difficult to evaluate the exact acidity or strength of long chain fatty acids like oleic acid. Since alcohol is a polar substance that long chain fatty acids are soluble in, it is used as a solvent to dissolve fatty acids, and its acidity is consequently determined by titrating it against an alcoholic potassium hydoxide solution.
<h3>
What is apparent acidity?</h3>
Fresh milk reacts with an acid due to its alleged apparent acidity. It is now generally accepted that it is caused by the carbon dioxide, acid phosphates, and casein present in fresh milk, all of which have an acidic nature.
<h3>
What is oleic acid?</h3>
Various animal and vegetable fats and oils naturally include the fatty acid oleic acid. It is an odorless, colorless oil, however commercial examples may be yellowish. Oleic acid, whose lipid number is 18:1 cis-9, is a monounsaturated omega-9 fatty acid according to chemical classification.
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The difference between Argon-38 and Argon - 45 is the number of neurons in their nuclei.
<h3>
What is Isotope?</h3>
Isotopes are two or more types of atoms of the same element that have the same atomic number but differs in mass numbers due to different numbers of neutrons in their nuclei.
Argon atom with a mass number of 38 (Ar-38) - number of neutrons = 20
Argon atom with a mass number of 45 (Ar-45) - number of neutrons = 27
Thus, the difference between Argon-38 and Argon - 45 is the number of neurons in their nuclei.
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Answer:
5 this is the answer call me brainy please
Astronomers classify stars according to their physical characteristics. Characteristics used to classify stars include color, temperature, size, composition, and brightness. Stars vary in their chemical composition.
A:- sn(s) => Sn +2(0.24 M) + 2e-
B:- Sn +2 (0.87 M) +2e- => Sn(s)
solution will become more concentrated and solution B become less concentrated
Sn(s)+ Sn +2(0.87 ) ----> Sn(s) + Sn +2(0.24)
E = Eo - 0.0592 / 2 * log [ (0.24 / 0.87 ) ]
E = 0.0 - 0.0592 / 2 * log ( 0.275)
( n=2 two electrons are transferred)
E = -0.0296 * ( - 0.560)
E = 0.0165 volts
