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Arte-miy333 [17]
3 years ago
13

Gift points I'm sad..........​

Chemistry
2 answers:
Naddika [18.5K]3 years ago
8 0

Awh, why are you sad? :(

Sloan [31]3 years ago
5 0

Me too hun

<3 + :( = :) :) ???

You might be interested in
Many common liquids have boiling points that are less than 110°C, whereas most metals are solids at room temperature and have mu
Semmy [17]

Answer:

1. 315.4 K

2. 1560 °C

Explanation:

To convert from celsius to Kelvin, the following formula can be used:

T(K) = T(°C) + 273

Where:

T(K) => Temperature in Kelvin

T(°C) => Temperature in degree celsius

1. Determination of the temperature in Kelvin.

Temperature (T) in °C = 42.4 °C.

Temperature (T) in K =?

T(K) = T(°C) + 273

T(K) = 42.4 °C + 273

T(K) = 315.4 K

2. Determination of the temperature in degree Celsius.

Temperature (T) in K = 1833 K

Temperature (T) in °C =?

T(K) = T(°C) + 273

1833 = T(°C) + 273

Collect like terms

T(°C) = 1833 – 273

T(°C) = 1560 °C

7 0
3 years ago
An aqueous solution of 1.29 M ethanol, CH3CH2OH, has a density of 0.988 g/mL. The percent by mass of CH3CH2OH in the solution is
anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g

Now, the mass of the ethanol:

m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g

Finally, the by mass percent is:

m/m=\frac{59.34g}{988g}*100\\%

%m=6%

Best regards.

4 0
3 years ago
A chemistry student needs of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student dis
galben [10]

Answer:

The answer is "7.90 \ g".

Explanation:

Please finds the complete question in the attached file.

Volume = 10.0 \ mL \\\\Density =0.79 g\  cm^3

\text{Density}=\frac{Mass}{Volume}

Mass = Density \times Volume

         =(0.790 g\ cm^3) \times 10.0 \ mL\\\\=7.90 \ g

The mass of acetone to be weighed is 7.90 \ g

8 0
3 years ago
What is the easiest way to determine the reactivity of an element
makkiz [27]

I know the answer to your question but if you want me to answer this question first, I need your help with my question "How do I solve number 12? Quick please I need help ASAP!!!"

4 0
3 years ago
How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


5 0
3 years ago
Read 2 more answers
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