Answer:
5.00 g of solute will remain undissolved at the bottom of the container
Explanation:
From the question, the solubility of the solute in the given solvent is 45.0 grams of solute per 500 grams of solvent.
Now if i pour 50.0 grams of solute into 800 grams of solvent, it means that only 45 g will dissolve in 500 g of solvent leaving the additional 5 g undissolved.
Hence, 5 g of solute will remain undissolved at the bottom of the container.
(4) titration, the process of using an aqueous solution of known concentration to determine the concentration of another solution of unknown concentration, is your answer.
Answer:
the molecules of each substance attract each other through dispersion (London) intermolecular force.whether a substance is solid, liquid or gas depends on the balance between the kinetic energies of the molecules and their intermolecular attractions.
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Answer:
N-ethyl-2-methylpropan-2-amine
Explanation:
In this case, we have to start with the <u>IR info</u>. The signal on 3400 cm^-1 indicates the presence of a <u>hydrogen bonded to the heteroatom</u>. In this case, we have nitrogen in the formula, so we will have the <u>amine group</u>.
On the other hand, we have to analyze the NMR info:
a) We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.
b) We have a triplet => This indicates the presence of <u>CH3 bonded to a CH2</u>.
c) We have a quartet => This indicates the presence of <u>CH2 bonded to a CH3</u>.
From b) and c) we can conclude that we have the <u>ethyl group</u> bonded to a nitrogen.
Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the <u>ter-butyl group</u>.
In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group
The concentration of a substance is the quantity of solute present in a given quantity of solution.