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MakcuM [25]
3 years ago
15

Density can be calculated by dividing an object's mass by its volume. If the mass of an object is 10 grams and its volume is 2 m

illiliters, what is its density?
Chemistry
1 answer:
Luden [163]3 years ago
6 0

Explanation:

  1. mass =10g. volume=2ml. density=mass/volume = 10/2=5kg/m^3
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What is the mass (in g) of 0. 935 mol of acetone CH3COCH3 the molar mass of acetone is 58. 08 g∙mol^–1.
Ray Of Light [21]

Answer:

54.30 grams acetone

Explanation:

(0. 935 mol)*(58.08 g/mole) = 54.30 grams acetone

4 0
1 year ago
Read 2 more answers
What is the S.I unit of pressure?
Vesna [10]

Answer:

pascal(pa)

Explanation:

the unit of pascal (pa), defined as a force of one newton per square meter. the conversion between atm ,pa, torr is as follow : 1 atm =101325 pa= 760 torr.

5 0
3 years ago
Be sure to answer all parts. What is the effect of each of the following on the volume of 1 mol of an ideal gas? (a) The pressur
aksik [14]

Answer

A)The volume decreases by a factor of 4

B), the volume has increased by factor of 2

Explanation:

A)Given:

P1= 760Kpa

P2 =202Kpa

The temperature changes from37C to155C

There is increase In pressure from P1 to P2

P1= 760torr.

We need to convert to Kpa

But, 1atm= 760torr

Then 760torr 101000pa

Then 101000pa = 101Kpa

We need to convert the temperature from Celsius to Kelvin

T1= 37+273= 310K

But from ideal gas, we know that PV = nRT where nR is constant

Where P= pressure

V= volume

T= temperature

n = number of moles

(P1V1/T1)=(P2V2/T2)

V1/V2 = P2/P1 * T1/T2

V1/V2 = (202/101)*(310/155)

V1/V2=4

V2= V1/4

Therefore, the volume has decreased by factor of 4

B)

Given:

P1= 2atm

P2 =101Kpa

The temperature changes from 305K to 32C

There is increase In pressure from P1 to P2

P1= 2atm

We need to convert to Kpa

But, 1atm= 760torr

Then 760torr 101000pa

Then 101000pa = 101Kpa

P1= 202.65kpa

We need to convert the temperature from Celsius to Kelvin

T2= 32+273= 305K

But from ideal gas, we know that PV = nRT

Where P= pressure

V= volume

T= temperature

n = number of moles

(P1V1/T1)=(P2V2/T2)

V1/V2 = P2/P1 * T1/T2

V1/V2 = (202/101)

V1/V2 = (101/202.65)*(305/305)

V1/V2 = 1/2

V2=2V1

Therefore, the volume has increased by factor of 2

4 0
3 years ago
Do you know any of these?
bulgar [2K]
The second one is no
6 0
3 years ago
Read 2 more answers
How many moles are in 187.54 grams of magnesium chlorate?
Svetlanka [38]

Hey there!

Magnesium chlorate: Mg(ClO₃)₂

Find molar mass.

Mg: 1 x 24.305 = 24.305

Cl: 2 x 35.453 = 70.906

O: 6 x 16 = 96

------------------------------------

                      191.211 g/mol

We have 187.54 grams.

187.54 ÷ 191.211 = 0.9808

There are 0.9808 moles in 187.54 grams of magnesium chlorate.

Hope this helps!

3 0
3 years ago
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