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Anton [14]
3 years ago
13

Which one is fossil fuel 1 fire wood 2 coal 3 bio-gas4 fire cakes​

Chemistry
1 answer:
Tpy6a [65]3 years ago
5 0
2.) coal is the correct answer!
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Calculate Density:<br> Volume=13cm3, Mass=147.55g<br> Someone please help
almond37 [142]

Answer:

11.35 g/cm³

Explanation:

If your rounding then 11.4. hope this helps :)

5 0
2 years ago
If faucet drips 5 mL of water each minute, what is the volume of water dripped at the end of five minutes?
kiruha [24]
If the faucet drops at 5 mL per minute you just have to do the following steps to find out.

5 mL for the dripping rate times 5 for the minutes.

The answer would result being 25mL

Hope this helps! Stay safe!
6 0
3 years ago
Read 2 more answers
What reaction might we use to synthesize nickel sulfate,niso4? Write equations for acid base neutralization. Include states in y
il63 [147K]

Answer:

Here's what I get  

Explanation:

1. Nickel sulfate

base + acid ⟶ salt + water

NiSO₄ is a salt of the base Ni(OH)₂ and the acid sulfuric acid.

Hydroxides of transition metals are insoluble; most sulfates are soluble.

\underbrace{\hbox{Ni(OH)$_{2}$(s)}}_{\hbox{base}} + \underbrace{\hbox{H$_{2}$SO$_{4}$(aq)}}_{\hbox{acid}} \longrightarrow \, \underbrace{\hbox{NiSO$_{4}$(aq)}}_{\hbox{salt}} + \underbrace{\hbox{2H$_{2}$O(l)}}_{\hbox{water}}

2. Carbonate + acid

Most carbonates are insoluble.

They react with acids to form carbonic acid (H₂CO₃), which decomposes into water and carbon dioxide.

\rm NiCO_{3}(s) + H_{2}SO_{4}(aq) \longrightarrow \, NiSO_{4}(aq) + H_{2}O(l) + CO_{2}(g)

5 0
3 years ago
Validate how valence electrons determine the chemical reactivity of an element: give 2 examples of elements with high reactivity
Ostrovityanka [42]
Nitrogen is more reactive than oxygen and oxygen than chlorine
8 0
3 years ago
#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
Murljashka [212]

Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

7 0
3 years ago
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