The Change in Gibb's free energy, ΔG for the reaction at 298K is; -56.92KJ.
<h3>Gibb's free energy of reactions</h3>
It follows from the Gibb's free energy formula as expressed in terms of Enthalpy and Entropy that;
On this note, it follows that;
Hence, the Gibb's free energy for the reaction is;
- ΔG = 14.6 - 71.52
- ΔG = -56.92KJ
Remarks: The question requires that we determine the Gibb's free energy for the reaction at 298K.
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Answer:
Statements Y and Z.
Explanation:
The Van der Waals equation is the next one:
(1)
The ideal gas law is the following:
(2)
<em>where n: is the moles of the gas, R: is the gas constant, T: is the temperature, P: is the measured pressure, V: is the volume of the container, and a and b: are measured constants for a specific gas. </em>
As we can see from equation (1), the Van der Waals equation introduces two terms that correct the P and the V of the ideal gas equation (2),<u> by the incorporation of the intermolecular interaction between the gases and the gases volume</u>. The term an²/V² corrects the P of the ideal gas equation since the measured pressure is decreased by the attraction forces between the gases. The term nb corrects the V of the ideal gas equation, <u>taking into account the volume occuppied by the gas in the total volume, which implies</u> a reduction of the total space available for the gas molecules.
So, the correct statements are the Y and Z: the non-zero volumes of the gas particles effectively decrease the amount of "empty space" between them and the molecular attractions between gas particles decrease the pressure exerted by the gas.
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I believe the a is the correct answer is d
B. the shape of a molecule determines its properties and interactions