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3 years ago

Consider this question: What is the molarity of KMnO4 in a solution of 0.0908 g of KMnO4 in 0.500 L of solution?

Chemistry

1 answer:

natita [175]3 years ago

6 0

Answer:

0.0011 M.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = given mass of KMnO₄ = 0.0908 g

and ,

V = 0.500 L

Since ,

we know ,

m = Molecular mass of KMnO₄ = 158 g/mol

using , the above formula to calculate the moles ,

n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol

now , calculating the molarity as ,

M = n / V = 0.00057 mol / 0.500 L = 0.0011 M.

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Gold (111) Chloride

ZanzabumX [31]

Answer:

Explanation:

Gold (111) Chloride:

AuCl₃

The oxidation state of gold is +3.

Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.

When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.

Calcium Carbonate:

CaCO₃

Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.

When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.

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4 0

3 years ago

Consider the following elementary reaction:

Marat540 [252]

Answer:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

Explanation:

Hello!

In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:

$r=-k_1[NO]+k_{-1}[N_2O_2]$

However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:

$0=-k_1[NO]+k_{-1}[N_2O_2]$

Which can be also written as:

$k_1[NO]=k_{-1}[N_2O_2]$

Then, we solve for the concentration of NO to obtain:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

Best regards!

8 0

3 years ago

A 125G sample of water was heated to 100.0°C and then I borrow platinum 20.0°C is dropped into the beaker the temperature of the

Sophie [7]

Answer:

mass of platinum = 2526.12 g

Explanation:

Given data:

Mass of water = 125 g

Initial temperature of water= 100.0°C

Initial temperature of Pt = 20.0°C

Final temperature = 235°C

Specific heat of Pt = 0.13 j/g°C

Specific heat of water = 4.184 j/g°C

Mass of platinum = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q(w) = Q(Pt)

m.c. (T2 - T1) = m.c. (T2 - T1)

125 g × 4.184 j/g°C × (235°C - 100.0°C) = m × 0.13 j/g°C × (235°C - 20°C)

125 g × 4.184 j/g°C × 135°C = m × 0.13 j/g°C × 215°C

70605 j = m×27.95 j/g

m = 70605 j /27.95 j/g

m = 2526.12 g

5 0

4 years ago

2. Which of these combinations of elements are most likely to react to form ionic compounds?

Juliette [100K]

Answer:

b? prob

Explanation:

6 0

3 years ago

How would you calculate the molar mass of 2AgCl?

Rashid [163]

2 × (atomic mass of Ag) + (atomic mass of Cl (

3 0

3 years ago