Internal pressure is a measure of how the internal energy of a system changes when it expands or contracts at constant temperature.
Mole fraction = moles of desired compound / total moles
moles = mass (g) / molar mass (g/mol)
Mass of sucrose = 20.0 g
Moles of sucrose = 20.0 g / 342.3 g/mol = 0.058 mol
Mass of water = 100.0 g
Molar mass of water = 18 g/mol
Moles of water = 100.0 g / 18 g/mol = 5.556 mol
Total moles = moles of sucrose + moles of water
= 0.058 mol + 5.556 mol
= 5.614 mol
Mole fraction of sucrose = moles of sucrose / total number of moles
= 0.058 mol / 5.614 mol
= 0.010
Shorthand notations are a part of the Wolfram Language's rich syntax system that allows multiple ways to feed arguments to functions. In addition to creating compact code, using shorthand notation lets you customize your workflow in the Wolfram Language.
<h3>What is the shorthand notation of an atom?</h3>
Often, a shorthand method is used that lists only those electrons in excess of the noble gas configuration immediately preceding the atom in the periodic table. For example, sodium has one 3s electron in excess of the noble gas neon (chemical symbol Ne, atomic number 10), and so its shorthand notation is [Ne]3s1.
<h3>How do you write shorthand configuration?</h3>
In shorthand electron configuration, the electron configuration starts with the symbol of the noble gas in the previous period, followed by the additional configuration of the electrons for the given element. For example, aluminum has the atomic number 13, which is the number of protons in the nuclei of its atoms.
Learn more about shorthand notation here:
<h3>
brainly.com/question/14177699</h3><h3 /><h3>#SPJ4</h3>
To change a gas to a liquid, you will need to lower the surrounding temperature. The condensation point is the temperature when the gas becomes a liquid.
Answer:
The mass of copper that was heated is 30 g
Explanation:
The formula for the heat supplied, ΔH is;
ΔH = m·c·Δt
Where:
ΔH = Heat supplied = 480 J
m = Mass of the copper sample = Required
c = Specific heat capacity of copper = 0.4 J/(g·°C)
Δt = Change in temperature = T₂ - T₁ = 60° - 20° = 40°C
T₁ = Initial temperature = 20°C
T₂ = Final temperature = 60°C
Therefore, plugging the values, we have;
480 = m×0.4×40
m = 480/(0.4 × 40) = 30 g
The mass of copper that was heated = 30 g.