evaporation. When a substance undergoes a change of matter from a solid to gas, it is the process of evaporation.
Hope this helps
Answer:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in
which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Explanation:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
⇄ ![H^+ + HCO^-_{3}](https://tex.z-dn.net/?f=H%5E%2B%20%2B%20HCO%5E-_%7B3%7D)
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in
which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Answer: Option (d) is the correct answer.
Explanation:
It is given that molecular formula is
. Now, we will calculate the degree of unsaturation as follows.
Degree of unsaturation = ![C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1](https://tex.z-dn.net/?f=C_%7Bn%7D%20-%20%5Cfrac%7B%5Ctext%7Bmonovalent%7D%7D%7B2%7D%20%2B%20%5Cfrac%7B%5Ctext%7Btrivalent%7D%7D%7B2%7D%20%2B%201)
= ![9 - \frac{16}{2} + 1](https://tex.z-dn.net/?f=9%20-%20%5Cfrac%7B16%7D%7B2%7D%20%2B%201)
= 9 - 8 + 1
= 2
As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.
Yes, this compound could be an alkyne as for alkyne D.B.E = 2.
But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.
Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.
1.0 mole ---------- 6.02x10²³ molecules
4.5 moles -------- ?
4.5 * 6,02x10²³ / 1.0
= 2.709x10²⁴ molecules units
Answer:
A lot, because it belt inclined at an angle of 36.9° above the horizontal.
I need points haha!