X = adults
Y = child
X+y=168
X=168-y
$10x + $7y = $1446
10(168-y) + 7y = 1446
1680 - 10y + 7y = 1446
-3 y = -234
Y = 78
X = 168-78
X = 90
$10*90 + $7*78 =
$900 + $546 = $1446
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Hi, sorry i couldn't understand the format of the question, could you post a picture of the question please?
Answer:
48.1 m³ available, 2.5m³ not available
Step-by-step explanation:
Tan(X) = 4.5/(5.8+1.7)
Tan X = 3/5
Hypotenuse² = 3² + 5² = 34
Sin X = 3/sqrt(34)
X = 30.96
1/sinX = 1.7/SinY
Y = 61.003°
Third angle: 180 - X - Y = 88.037
Volume
= ½ × 1.7 × 1 × sin(88.038) × 3
= .
= 2.548
= 2.5m³
Available for storage:
½×4.5×7.5×3 - 2.548
= 48.077 = 48.1 m³
