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sashaice [31]
2 years ago
11

What value of m would make the expression below simplified to 6x

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
3 0
I thinks it’s A because I did this before
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What is the least common multiple of 5 and 10
anyanavicka [17]
The least common multiple of 5 and 10 is 5. I hope this helps you.
6 0
3 years ago
Read 2 more answers
Point U has Coordinates (-5,1) and point V has coordinates (7,9) find the coordinates of the midpoint of UV
frutty [35]

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

Midpoint of a Line Segment:

A line segment's midpoint is a point that divides the line segment across two equal sections. The midpoint of a line segment with coordinates at both ends X₁ , Y₁ and  X₂, Y₂ is calculated using:

<h3>According to the given data:</h3>

Point U has Coordinates (-5,1).

point V has coordinates (7,9).

Find  coordinates of the midpoint of UV = ?

We know that to find Midpoint of a Line Segment:

                               = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Where U

           X₁ = -5

           Y₁ = 1

Whare V

           X₂ = 7

           Y₂ = 9

Putting the value in the formula:

UV = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

       = (-5 + 7)/2 , (1 + 9)/2

       = -6 , 5

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

To know more about Midpoint of a Line Segment visit:

brainly.com/question/13792156

#SPJ9

4 0
1 year ago
At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye
Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that \mu = 3125

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that n = 9, X = 2915, s = 585

What is the test statistic needed to evaluate the claim?

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}

t = -1.08

The test statistic needed to evaluate the claim is t = -1.08.

6 0
2 years ago
I really don’t know how to do this can someone help
Scorpion4ik [409]

Answer:

0.57

Step-by-step explanation:

6 0
3 years ago
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Parallelogram ABCD is similar to the parallelogram EFGH. What is the length of GH? 
laiz [17]

Answer:

2 in

Step-by-step explanation:

3 0
3 years ago
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