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sashaice [31]
2 years ago
11

What value of m would make the expression below simplified to 6x

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
3 0
I thinks it’s A because I did this before
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10x4ones= ones=<br> 10x2tens= tens=
Vsevolod [243]
Well, 10x4=40 because 10+10+10+10=40 and that means your answer must be 40 ones or you asked something else.
5 0
3 years ago
0.000000205<br> In standard form
zalisa [80]

Answer:

2.05 × 10⁷

Step-by-step explanation:

0.000000205

We'll move the decimal point after the first non-zero digit (as per the scientific notation rules) and the standard form would be :

=> 2.05 × 10⁷

6 0
2 years ago
Read 2 more answers
Which statement follows from the given theorem? Theorem: The diagonal of a parallelogram divides it into two congruent triangles
Ivenika [448]

Answer:

SSS

Step-by-step explanation:

the dividing line would give the triangles the same length for one side, the side it divided, and then it says the triangles are congruent, meaning they are both the same triangle.

8 0
3 years ago
Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will
Paraphin [41]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill

7 0
3 years ago
Read 2 more answers
Determine the equation of the circle graphed below. <br> Please help, thanks
marusya05 [52]

Answer:

If you are finding the equation using two points then the answer is

y = −2 x + 1

If this does not help, just ignore honestly.

4 0
2 years ago
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