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sashaice [31]
2 years ago
11

What value of m would make the expression below simplified to 6x

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
3 0
I thinks it’s A because I did this before
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Because your slope is 3 when you do change in y over change in x. Y intercept is neg 4.
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2 years ago
Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
3 years ago
3 ÷ 1/2 what is it?​
Alja [10]

3\div\dfrac{1}{2}=3\cdot2=6

8 0
3 years ago
Read 2 more answers
What is the speed (approximately) of a 2.5-kilogram mass after it has fallen freely from rest through a distance of 12 meters?
Norma-Jean [14]

Answer:

15.3 m/s

Step-by-step explanation:1) Find the gravitational potential energy using the equation :

     PE_g=mgh

    PE_g=2.5(12)(9.8)\\PE_g=294

2) Then use the equation for kinetic energy to solve for the velocity:

     KE=\frac{1}{2} mv^{2}

     294=\frac{1}{2}(2.5)(v^2)\\235.2=v^2\\\sqrt{235.2} =v\\15.3 m/s=v

6 0
3 years ago
Resuelve el siguiente problema aplicando las estrategias de solución de problemas.
scoundrel [369]
Say it in english so i cant try to help
7 0
2 years ago
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