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Answer:
The diffusion coefficients for iron in nickel are given at two temperatures:
T (K) 1273 1473
D (/s) 9.4 × 2.4 ×
(a) Determine the values of Do and the activation energy Qd.
(b) What is the magnitude of D at 1100°C (1373 K)?
<em>A </em>
<em>The pre-exponential factor Do = 2.1 x </em><em></em>
<em>The activation energy Qd = 252,609 J/mol</em>
<em>B</em>
<em>The diffusion coefficient D= 5.14 x </em><em></em>
Explanation:
The full explanation is contained in the attached images;
Explanation:
Ohm's law applies: V = IR, and variations. The current in a series circuit is the same through every element. That current is given as 1.1 A.
Rt = (8 V)/I3 = (8 V)/(1.1 A) = 80/11 Ω = 7 3/11 Ω
R3 = Rt -R1 -R2 = 7 3/11 -2 -5 = 3/11 Ω
It = I3 = 1.1 A
I1 = I2 = I3 = 1.1 A
V1 = (I1)(R1) = (1.1 A)(2 Ω) = 2.2 V
V2 = (I2)(R2) = (1.1 A)(5 Ω) = 5.5 V
V3 = (I3)(R3) = (1.1 A)(7/11 Ω) = 0.3 V
The efficiency of a transformer is mainly dependent on a)- Core losses
Hope this helps! :)