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4 years ago

What material resources and intellectual resources were used in self driving cars?

1 answer:

fomenos4 years ago

5 0

Answer: material resources: cameras, light detection and ranging systems, radar, sensors, advanced GPS, and millions of miles of training data, and more

I don't know about the intellectual resources sorry

You might be interested in

A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy (Animated Figure 9.8) is heated to 250°C; at this temperature it is entirely an

Alex17521 [72]

Answer:

A. By hit and trial method 280 C

Explanation:

ion know B sorry

6 0

2 years ago

A Capacitor is a circuit component that stores energy and can be charged when current flows through it. A current of 2A flows th

valkas [14]

Answer:

6uC

Explanation:

View Image

Derive an equation for charge(q) in term of current then solve:

$q(t)=\int\limits^\tau_{\tau_0} {i(t)} \, d\tau+q_0$

Use the equation above to solve for your net charge.

6 0

3 years ago

suppose we number the bytes in a w-bit word from 0 (less significant) to w/8-1 (most significant). write code for the followign

sammy [17]

Solution:

typedef unsigned char *byte_pointer;

static int int_of_bit (byte_pointer x, int loc)

{

return(x[loc] << loc*8);

}

static int replace_byte(unsigned int a, int loc, unsigned int b)

unsigned int a_loc = int_of_bit((byte_pointer) &a , loc);

unsigned int b_loc = (b << loc*8);

a -= a_loc;

a += b_loc;

return a;

}

Explanation:

This takes two ints in hex format, one with 8 bits (0x00000000) and one with 2 bits (0x00) then places the 2 bit hex into the 8 bit at a given location.

EX: replace_byte(0x00000000, 1, 0xFF) return 0x0000FF00

First thing first, it looks like you have some mixup:

" one with 8 bits (0x00000000) and one with 2 bits (0x00)*- what you mean is nibble not bits. Each hex character (0-9, A-F) represent 4 bits (16 possible combination), and is called a "nibble".

0x0000000 is 4 bytes. 0x00 is 2 bytes.

Next, you say "takes two ints in hex format" - your function takes two ints in any format. You're just choosing tp express them in hexidecimal. C++ doesn't care if you specify numbers in hex, decimal, octal, binary, etc.

8 0

3 years ago

An ideal Diesel cycle has a maximum cycle temperature of 2000°C. The state of the air at the beginning of the compression is P1

IrinaVladis [17]

Answer:

Power produced = 90.47 KW

Explanation:

We are given;

R = 0.287 kJ/kg·K

T1 = 15°C = 15 + 273 = 288 K

P1 = 95 KPa

Number of cylinders;N_cyl = 8

Bore;B = 10cm = 0.1m

Stroke;S = 12cm = 0.12m

cp = 1.005 kJ/kg·K

cv = 0.718 kJ/kg·K

k = 1.4

First of all let's find the initial specific volume;

α1 = RT1/P1

α1 = 0.287 * 288/95

α1 = 0.87 m³/kg

Now, let's find the total mass of air from the formula;

m =(V•N_cyl)/α1 =(B²•N_cyl•S•π)/4α1

So, m = (B²•N_cyl•S•π)/4α1

m = (0.1²•8•0.12•π)/(4*0.87)

m = 0.00867 Kg

Now, let's calculate the total mass flow rate;

m' = (m*N_rev)/n'

Where;

N_rev is number of revolutions given as 1500 rpm = 1500/60 rev/s = 25 rev/s

n' is the repetitions per circle = 2.

Thus;

m' = (0.00867*25)/2

m' = 0.108375 kg/s

The temperature at state 2 is gotten from the formula;

T2 = T1*r^(k - 1)

Where r is compression ratio.

We know that formula for compression ratio is;

the ratio of the maximum to minimum volume in the cylinder of an internal combustion engine.

In the question, we are told that minimum volume enclosed in the cylinder is 5 percent of the maximum cylinder volume.

Thus,

r = 100/5 = 20

So, T2 = 288*20^(1.4 - 1)

T2 = 954.563 K

The cut off ratio is gotten from the formula;

r_c = α3/α2 = T3/T2

T3 = 2000°C = 2000 + 273K = 2273K

Thus; r_c = 2273/954.563

r_c = 2.38

The heat input is gotten from the formula;

q_in = cp(T3 - T2)

q_in = 1.005(2273 - 954.563)

q_in = 1325.03 KJ/Kg

The efficiency is gotten from;

η = 1 - [1/(r^(k - 1)]*[((r_c)^(k) - 1)/(k(r_c - 1))]

Thus;

η = 1 - [1/(20^(1.4 - 1)]*[((2.38)^(1.4) - 1)/(1.4(2.38 - 1))]

η = 0.63

Now, the power output is gotten from the equation;

W' = m'•η•q_in

W' = 0.108375*0.63*1325.03

W' = 90.47 KW

7 0

3 years ago

H. Blasius correlated data on turbulent friction factor in smooth pipes. His equation f s m o o t h ≈ 0.3164 Re − 1 / 4 fsmooth≈

tiny-mole [99]

Answer:

Therefore the angle the pipe needed to make the static pressure constant along the pipe is θ = 4° 16'

Explanation:

The first step to take is to calculate the the velocity of flow through a pipe

Q =Av

Where Q = is the discharge through pipe

A = Area of the pipe

v = the flow of velocity

We substitute 0.001 m^3/s for Q and 0.03 m for D

Q= Av

0.001=Av

Substitute π/4 D² for A

0.001 = π/4 D² (v)

v = 0.004/πD²

D = he diameter of the pipe

substitute 3 cm for D

v= 0.004/π * [3 cm * 1 m/100 cm]²

v =1.414 m/s

Obtain fluid properties from the table Kinematic viscosity and Dynamic of water

p =1000 kg /m³

μ= 1.002 * 10^ ⁻³ N.s/m³

Thus,

we write the expression to determine the Reynolds number of flow

Re = pvD/μ

Re = is the Reynolds number

p =density

μ = dynamic viscosity at 20⁰C

We then substitute 1000 kg /m³ in place of p, 1.002 * 10^ ⁻³ N.s/m³ for μ,

1.414 m/s for v and 0.03 m for D

Thus,

Re = 1000 * 1.414 * 0.03/ 1.002 * 10^ ⁻³ = 42335

The next step is to calculate the friction factor form the Blasius equation

f = 0.3164 (Re)^1/4

f = friction factor

We substitute 42335 for Re

f = 0.3164 (42335)1/4

=0.022

The next step is to write the expression to determine the friction head loss

hl = flv²/2gD

hl = head loss

l = length of pipe

g= acceleration due to gravity

We then again substitute 0.022 for f, 1.414 m/s for v, 0.03 m for D, and 9.8 m/s² for g.

so,

hl = flv²/2gD

hl/L = 0.022 * 1.414²/2 * 9.81 * 0.03

sinθ = 0.07473

θ = 4° 16'

Therefore the angle the pipe needed to make the static pressure constant along the pipe is θ = 4° 16'

3 0

3 years ago