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Agata [3.3K]
3 years ago
8

Can a 1½ " conduit, with a total area of 2.04 square inches, be filled with wires that total 0.93 square inches if the maximum f

ill for that conduit is 40%?
Engineering
1 answer:
Papessa [141]3 years ago
4 0

Answer:

it is not possible to place the wires in the condui

Explanation:

given data

total area = 2.04 square inches

wires total area = 0.93 square inches

maximum fill conduit =  40%

to find out

Can it is possible place wire in conduit conduit

solution

we know maximum fill is 40%

so here first we get total area of conduit that will be

total area of conduit = 40% × 2.04

total area of conduit = 0.816 square inches

but this area is less than required area of wire that is 0.93 square inches

so we can say it is not possible to place the wires in the conduit

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Explanation:

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4 0
2 years ago
During January, at a location in Alaska winds at -20°C can be observed, However, several meters below ground the temperature rem
maw [93]

Answer:

a) \eta_{th} = 10.910\,\%, b) Yes.

Explanation:

a) The maximum thermal efficiency is given by the Carnot's Cycle, whose formula is:

\eta_{th} =\left(1-\frac{253.15\,K}{284.15\,K}  \right) \times 100\,\%

\eta_{th} = 10.910\,\%

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4 0
3 years ago
A transmission line (TL) of length L and conductance per unit length G' is connected to an ideal constant voltage generator V. T
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Answer:

The Current will decrease by a factor of 2

Explanation:

Given the conditions, it should be noted that the current in the circuit is determined by the LOAD. In other words, the amount of current generator will be producing depends upon the load connected to it.

Now, as the question says, the load is reduced to half its original value, we can write:

P1 = \sqrt{3} (V) (I1) Cos\alpha ----- (1)

P2 = \sqrt{3} (V) (I2) Cos\alpha\\

Since, P2 = P1/2,

P1/2 = \sqrt{3} (V) (I2) Cos\alpha ----- (2)\\

Dividing equations (1) and (2), we get,

P1 / (P1/2) = I1/ I2

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7 0
3 years ago
1. Give the most space to
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Closest one is A. “The largest Vehicle”
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3 years ago
2. How many amperes of current will flow through a circuit that has 3 ohms of resistance if
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Answer:

4A

Explanation:

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I= 4 A

4 0
3 years ago
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