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2 years ago

Two basic types of mechanical fuel injector systems?

Engineering

2 answers:

dem82 [27]2 years ago

7 0

Answer:

excretory system oxgen

REY [17]2 years ago

4 0

Answer:

Single-point or throttle body injection. Port or multipoint fuel injection.

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Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the array's

atroni [7]

Answer:

See below in the explanation section the Matlab script to solve the problem.

Explanation:

prompt='enter the first weight w1: ';

w1=input(prompt);

wd1=double(w1);

prompt='enter the second weight w2: ';

w2=input(prompt);

wd2=double(w2);

prompt='enter the third weight w3: ';

w3=input(prompt);

wd3=double(w3);

prompt='enter the fourth weight w4: ';

w4=input(prompt);

wd4=double(w4);

prompt='enter the first weight w5: ';

w5=input(prompt);

wd5=double(w5);

x=[wd1 wd2 wd3 wd4 wd5]

format short

6 0

2 years ago

(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compa

ludmilkaskok [199]

Answer:

70.66 cm^3

The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )

Explanation:

Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----

Viral equation can also be rewritten as :

Z = 1 + B ( P/RT )

B ( function of time )

Temperature = 310 K

P1 = 8 bar

P2 = 75 bar

Determine the specific volume in cm^3

V = 70.66 cm^3

b) comparing the specific volumes to the experimental values

70.58 and 3.90

The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )

attached below is the detailed solution

3 0

2 years ago

Cold forging makes metal more workable than hot forging. True False

Whitepunk [10]

Answer:

I don't really know but i have some info for you...

Explanation:

The cold forging manufacturing process increases the strength of a metal through strain hardening at a room temperature. On the contrary the hot forging manufacturing process keeps materials from strain hardening at high temperature, which results in optimum yield strength, low hardness and high ductility.

7 0

2 years ago

Read 2 more answers

A reversible refrigeration cycle operates between cold and hot reservoirs at temperatures TC and TH, respectively. (a) If the co

podryga [215]

Answer:

a) $T_{H} = 1.967\,^{\circ}F$ , b) $COP_{R} = 9.105$ , c) $T_{H} = 115.934\,^{\circ}F$ , d) $COP_{R} = 6.995$ , e) $T_{H} = 25.129\,^{\circ}C$

Explanation:

a) The coefficient of performance of the reversible refrigeration cycle is:

$COP_{R} = \frac{T_{C}}{T_{H}-T_{C}}$

$10 = \frac{419.67\,R}{T_{H}-419.67\,R}$

The temperature of the hot reservoir is:

$10\cdot T_{H} - 4196.7 = 419.67$

$T_{H} = 461.637\,R$

$T_{H} = 1.967\,^{\circ}F$

b) The coefficient of performance is:

$COP_{R} = \frac{273.15\,K}{303.15\,K-273.15\,K}$

$COP_{R} = 9.105$

c) The temperature of the hot reservoir can be determined with the help of the following relation:

$\frac{Q_{C}}{Q_{H}-Q_{C}} = \frac{T_{C}}{T_{H}-T_{C}}$

$\frac{500\,BTU}{600\,BTU-500\,BTU} = \frac{479.67\,R}{T_{H}-479.67\,R}$

$5 = \frac{479.67\,R}{T_{H}-479.67\,R}$

$5\cdot T_{H} - 2398.35 = 479.67$

$T_{H} = 575.604\,R$

$T_{H} = 115.934\,^{\circ}F$

d) The coefficient of performance is:

$COP_{R} = \frac{489.67\,R}{559.67\,R-489.67\,R}$

$COP_{R} = 6.995$

e) The temperature of the cold reservoir is:

$8.9 = \frac{268.15\,K}{T_{H}-268.15\,K}$

$8.9\cdot T_{H} - 2386.535 = 268.15$

$T_{H} = 298.279\,K$

$T_{H} = 25.129\,^{\circ}C$

8 0

2 years ago

What is the angle of the input

olga55 [171]

Absolute positions — latitudes and longitudes
Relative positions — azimuths, bearings, and elevation angles
Spherical distances between point locations

3 0

2 years ago

Two basic types of mechanical fuel injector systems?​

Two basic types of mechanical fuel injector systems?