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Nastasia [14]
3 years ago
6

YALL HAVE BEEN GETTING THESE WRONG LATELY SO PLZ HELP HELP

Mathematics
2 answers:
krok68 [10]3 years ago
4 0

Answer: use the brainly app on your phone the take a picture of it

Step-by-step explanation:

givi [52]3 years ago
4 0

Answer:

<em>m=-4/3</em>

Step-by-step explanation:

The equation for slope is y2-y1/x2-x1

m=(y2-y1)/(x2-x1)

m=(12--4)/(1-13)

m=16/-12

m=-4/3

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A babysitter earns $24 for 2 hours and $42 for 4 hours. Determine the rate of change
dedylja [7]

Answer:

im not 100% sure but this is the answer i got you need to add a number to that to get the next payment for 6 hours

Step-by-step explanation:

8 0
3 years ago
How do you solve for x/3 - x/5
ch4aika [34]

Answer:

x/3 - x/5 = 2/15x

Step-by-step explanation:

Please mark brainlliest if you want.

8 0
3 years ago
At the Souvenir Shop, gemstone souvenirs cost $11.60 for 5. Which proportion can be used to find the cost of just 1 gemstone?
Natasha2012 [34]

Answer:

see below

Step-by-step explanation:

$11.60 for $5

1. Find the rate.

$11.60 divided by $5= $2.32

2. 1 gemstone= $2.32

Your anwser should be 1 over $2.32 or $2.32 over 1 depending on how you want it.

5 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
4 years ago
When you skip count by 36 and 60 can it go into 144
natka813 [3]
No because 60 would not go evenly in for it is counting in the tens
3 0
3 years ago
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