Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575
Z = (X - x_bar)/sigma
Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18
From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714
P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316
The correct answer is C.
-2x-11 is equivalent to 3x-4-(5x+7)
Answer:
hmm...
Step-by-step explanation:
Answer:
103.468 rounded to the hundred is 103.500
Step-by-step explanation:
5 or above give it a shove
