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iren2701 [21]
3 years ago
12

A factory store has two types of machines.

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

c or d maybe d

Step-by-step explanation:

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Please help me with this question!
serg [7]

Answer:

It is perpendicular

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
PLZ HELP ill GIVE BRAINIESt!!!!32 Points
NISA [10]
We are given 2 points with there coordinates easy to calculate:

the upper one A(1,15) & the lower one B(6,10). Moreover the equation of this linear function is y = mx + b

1st) calculate m= (10-15) / (6-1)  [FOMULA m=(y₂ - y₁) / (x₂ - x₁)]

m= -5/5 ==> m= - 1==> y=-x + b. To calculate b, replace x & y by any of the 2 points A, B. Say A(1,15)

15 = - (1) + b ==> b= 16 & final equation y = -x +16


3 0
3 years ago
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Which are the coordinates of the x-intercept in the equation -4x + 5y = 20?
forsale [732]

Answer:

The x intercept is (-5,0)

Step-by-step explanation:

1. First, it would be helpful to rewrite the equation to be in y=mx+b form.

5y=4x+20

y=(4/5)x+4

2. Then, plug in 0 for y.

0=(4/5)x+4

3. Then, solve.

-4=(4/5)x

-20=4x

x=-5

7 0
3 years ago
Find 6m if m = 5/13<br><br>6 5/13 <br><br>5<br><br>2 4/12<br><br>5/78
Effectus [21]
M= 5/13
6m= 6(5/13)
6m = 30/13
7 0
3 years ago
Find the range of F<img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B2%7D%7Bx-7%7D%20" id="TexFormula1" title="f(x)= \fr
steposvetlana [31]
Answer: y \in R; y \neq 0
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.

Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

Now, since we know the end behaviours, let's find the asymptotic behaviours.

As x  approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.

So, our range would be: y \in R; y \neq 0
6 0
3 years ago
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