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ludmilkaskok [199]
2 years ago
13

Methane gas is collected over water at 25 C and an atmospheric pressure of 775 mmHg. What is the dry pressure of the gas at this

temperature? (Vapor Pressure of water = 0.0313 atm).
Chemistry
1 answer:
Pachacha [2.7K]2 years ago
6 0

Answer:

25775 = 0.0313

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Answer:

1.37cm

Explanation:

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For which elements are outer electrons and valence electrons the same?
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At 500 degree C, F_2 gas is stable and does not dissociate, but at 840 degree C, some dissociation occurs: F_2 (g) 2 F(g). A fla
bazaltina [42]

Answer:

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

Explanation:

F_2(g)\rightleftharpoons 2F(g)

Initial

0.600 atm    0

Equilibrium

(0.600 atm - p)        2p

Total pressure at equilibrium = P = 0.984 atm

P= 0.600 atm - p)+2p=0.984 atm

p = 0.384 atm

Partial pressure of the F_2 gas , p_{f_2}= (0.600 atm - 0.384 atm)=0.216 atm

Partial pressure of the F gas, p_{f} = 2(0.384 atm)=0.768 atm

K_p=\frac{(p_{F})^2}{p_{F_2}}

K_p=\frac{(0.768 atm)^2}{0.216 atm}=2.73

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

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