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Pachacha [2.7K]
3 years ago
5

A positively charged atom has? 1. gained protons. 2. gained electrons. 3. lost electrons. 4. lost protons.

Physics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

3. lost electrons.

Explanation:

An atom that has lost an electron is positively charged because the number of protons is now greater than the number of electrons in the atom.

  • Protons are positively charged particles in an atom.
  • Electrons are negatively charged particles.
  • Neutrons do not carry any charges.

If the number of protons and electrons are the same, the atom has no charge

If the protons > electrons, the atom becomes positively charged

If electrons > protons, the atom becomes negatively charged.

Atoms becomes charged by losing or gaining electrons.

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Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

Magnetic Field, B = 0.10 T

Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

5 0
3 years ago
Why were epicycles necessary in ptolemy’s model of the universe?
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4 years ago
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The instrument used to measure the diameter of a thin wire is​
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micrometer is used to measure the diameter of a thin wire

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Magnesium hydroxide is used in? <br><br> soap<br><br> batteries<br><br> antacids<br><br> detergents
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A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

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