The distance traveled by the sprinter in meters is determined as 1.88 m.
<h3>Acceleration of the sprinter</h3>
The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.
The acceleration of the sprinter is calculated as follows;
Apply Newton's second law of motion as follows;
F = ma
a = F/m
where;
- F is the applied force by the sprinter
- m is mass of the sprinter
- a is acceleration of the sprinter
a = 693 N / 64 kg
a = 10.83 m/s²
<h3>Distance traveled by the sprinter</h3>
The distance traveled by the sprinter is calculated as follows;
s = ut + ¹/₂at²
where;
- u is initial velocity = 0
s = ¹/₂at²
where;
- t is time of motion
- a is acceleration
s = (0.5)(10.83)(0.59²)
s = 1.88 m
Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.
Learn more about distance here: brainly.com/question/2854969
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Answer:
you want to know newtons first law here.
Explanation:
An object that is at rest stays at rest or stays in motion.
Answer:
12 meters per second (12 m/s)
why?
Because if you divide 10 seconds by 10 and 120 by 10, you will get 12 meters in 1 second.
