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DedPeter [7]
3 years ago
10

Name and explain factors that contribute to destructive relationships

Physics
1 answer:
algol133 years ago
6 0

Answer:

The two factors that contribute to a detrimental relationship are infidelity and lack of communication. Further Explanation: Detrimental relationship is a type of harmful relationship that may hurt a person in a relationship. Detrimental is something that has a damaging and harmful effect on someone or something.

Explanation:

so the two factors are infidelity and lack of communication

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What is the necessary conditions for the production of sound?
TEA [102]

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Answer: Something that's vibrating, and you also need medium for those vibrations to start in.

I hope this helped!

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8 0
3 years ago
Rays traveling parallel to the principle axis of a concave mirror will reflect out through the mirrors focus?
abruzzese [7]

Answer:

True

Explanation:

When a ray travelling parallel to the principle axis of a concave mirror then the light ray reflect out through the mirrors and passing through the focus.

When a light ray travelling through focus of a concave mirror then after reflection the light ray reflect out through the mirror and  go parallel to principle axis.

Therefore, rays travelling parallel to the principle axis of a  concave mirror will reflect out through the mirrors focus.

It is true.

7 0
3 years ago
Read 2 more answers
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
4 years ago
Question 15)
RUDIKE [14]

Answer:

k Nishant

Explanation:

i think option A

8 0
3 years ago
Need help! Need help! Need help! Need help! Need help! Need help!
Maslowich

Answer:

i can help you i know this answer

5 0
3 years ago
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