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DiKsa [7]
3 years ago
14

A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?

Physics
1 answer:
MakcuM [25]3 years ago
8 0

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

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AleksandrR [38]

Answer:

e = 10 V

Explanation:

given,

number of the coaxial loops = 10

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magnitude of magnetic field =

B = 3 T + (2 T/s)*t.

B = ( 3+ 2 t ) T

induced potential difference = ?

At time = 2 s

we know,

induced emf

e = - N\dfrac{d\phi}{dt}

∅ = B . A

e = - N\dfrac{d(BA)}{dt}

e = - NA\dfrac{dB}{dt}

e = - 10 \times 0.5 \times \dfrac{d}{dt}(3 + 2 t)

e = - 10 \times 0.5 \times 2

e = -10 V

magnitude of induced emf

|e| = |-10 V|

e = 10 V

the induced potential difference in the loop = e = 10 V

7 0
3 years ago
the musical note A above middle C has a frequency of 440 Hz. If the speed of the sound is known to be 350 m/s, what is the wavel
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8 0
4 years ago
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Ick! Word problems! They suck. Okay so first of all you want to narrow it dow the equation.


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Step 2. Are you multiplying, dividing? (In this case your dividing)

Step 3. Divide.

I hope that helps.
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