Question

ALL ABSURD ANSWERS WILL BE REPORTED AND REMOVED!

Answer 1

Answer:

What is the amount of energy needed to change 20g of ice at 0°C to steam at 100°C?

A mattress you can fall back on.

Use the formula

q = m·ΔHf

where q = heat energy; m = mass; ΔHf = heat of fusion

q = (20 g)x(334 J/g)

q = 6680 J

Step 2: Heat required to raise the temperature of 0 °C water to 100 °C water

q = mcΔT

q = (20 g)x(4.18 J/g·°C)[(100 °C - 0 °C)]

q = (20 g)x(4.18 J/g·°C)x(100 °C)

q = 8360 J

Heat required to raise the temperature of 0 °C water to 100 °C water = 8360 J

Heat required to convert 100 °C water to 100 °C steam

q = m·ΔHv

where q = heat energy; m = mass; ΔHv = heat of vaporization

q = (20 g)x(2257 J/g)

q = 45140 J

Heat required to convert 100 °C water to 100 °C steam = 45140 J

Total energy required: 6680+8360+45140=60180 Joules

Or practically understanding it: about 20s in a 3000W kettle.