1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Assoli18 [71]
3 years ago
9

PLEASE HELP ME!!!!!!!!

Chemistry
2 answers:
Inessa05 [86]3 years ago
6 0
I think the answer is true am not sure tho.
VMariaS [17]3 years ago
3 0

Answer:

I think the answer is false

You might be interested in
What is it about the structure of magnesium atoms that makes them react more slowly than calcium atoms?
vovikov84 [41]
Is there any answer so I can answer it
7 0
3 years ago
in an oversight in the experiment jamie did not add the 4-5 additional drop of 6M JNO3. as result, will the reported number of m
kaheart [24]
The reported number of moles will be too low since the additional amount of oxygen is not included. It may be 6 drops but the molarity of the solution is 6M. this meas that for every ml of the JNO3 solution there is 6 moles of JNO3. In every mole of <span>JNO3 there are 3 moles of oxygen. So in every drop of oxygen there are 18 moles of oxygen. </span>
6 0
3 years ago
A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3). What mass of sodium hydroxide is
Karolina [17]

Answer:

3.94 × 10³ g

Explanation:

Step 1: Write the neutralization reaction

HClO₃ + NaOH = NaClO₃ + H₂O

Step 2: Calculate the moles of chloric acid that react

25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:

25.5L \times \frac{3.86mol}{L} =98.4mol

Step 3: Calculate the required moles of sodium hydroxide

The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.

Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles

The molar mass of NaOH is 40.00 g/mol.

98.4mol \times \frac{40.00g}{mol} =3.94 \times 10^{3} g

6 0
3 years ago
When would it be most appropriate to use ppm to describe the concentration of the solutes in a solution?
cluponka [151]

B) When describing very dilute solutions.

Explanation:

The most appropriate time to use ppm is when describing dilute concentrations of solutes in solutions. It is used mostly to determine trace amount of elements in water and soils.

  • The part per million ppm is the amount of miligram of a solute in a liter of solution.
  • It is similar to percentage.
  • Minute and trace concentrations are very difficult to work with.
  • Using parts per million, they become better appreciated and easy to use.

Learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

5 0
4 years ago
What is the mole ratio of <br> N2 + 3H2 Right arrow. 2NH3
Oksana_A [137]

Answer:mole ratio between N2 and 2NH3 is 1:2while mole ratio between H2 and 2NH3 is 3:2

Explanation: 1 mole of N2 is required to produce 2 moles of NH3 while 3moles of H2 is required to produce 2 moles of NH3

8 0
4 years ago
Other questions:
  • When increased, increases the rate of solution (2 words) not particle size
    12·1 answer
  • Which tools do you use to measure mass, length, volume, and temperature?
    10·2 answers
  • What isotope has 13 protons and 14 neutrons? Enter the name of the element followed by a hyphen and the mass number (e.g., urani
    9·1 answer
  • What mass of gold is produced when 23.8 a of current are passed through a gold solution for 36.0 min ?
    15·1 answer
  • How did rutherford contribute to atomic theory?
    5·1 answer
  • What is the number in scientific notation? ​0.000000000093 enter your answer in the box.
    6·1 answer
  • A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
    11·1 answer
  • 1. Which of the following statements is true about seeds?
    10·1 answer
  • Which of the following would be the best representation of input energy and then
    6·1 answer
  • Elemantal form of calcium
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!