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frozen [14]
3 years ago
14

Is O2 covalent molecular or polar covalent

Chemistry
1 answer:
Dimas [21]3 years ago
6 0
Yes it yes molusbus ks jshs jsbjsus js js sjs js sj dis dis jsys snsus
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An unknown atom has 5
labwork [276]

Answer:

17

Explanation:

the atomic mass is away protons + neutrons, electrons are neglatable.

7 0
3 years ago
Four acids are analyzed and there KA values are determined which of the following values represents the strongest acid
Advocard [28]

x= the coefficients in front of the substance in the balanced chemical equation  

[H+]= the concentration of hydrogen ions  

[A-]= the concentration of the other ion that broke off from the H+  

[HA]= the un-disassociated acid concentration  

The higher the Ka value, the greater amount of disassociation of the reactants into products. As for acids, they will break down to form H+ ions. The more the H+ ions, the stronger acidity of the solution. Thus since A has the highest Ka value, that represents the strongest acid.  

You can determine the Ka value from a number of ways. If equilibrium concentrations are given of a certain acid solution, you can find the proportion of the concentration of ions to the concentration of the remaining HA molecules, using the equation above. Also, pH and KpH can be used in a number of ways. This gets more complicated and depends on the situation, and requires more advanced equations.


Hope this helped a little, its obviously not my best work

6 0
3 years ago
Read 2 more answers
Please help with these questions ASAP will give brainlist!! CHEMISTRY
Irina18 [472]

Answer:

Question 1 is 21.0g

Explanation:

50 x 4.18 x 3.1 / 0.444 / 69.6= 21.0

4 0
3 years ago
The surface area of a star can be estimated based on the stars
azamat
Size (length+width) approx.
3 0
3 years ago
What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +
Mademuasel [1]

Answer: \Delta S^{0} for the reaction is -186.75 J/K

Explanation:

Change in entropy (\Delta S^{0}) for the given reaction under standard condition is given by-

\Delta S^{0}= [3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]

So \Delta S^{0} = [3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol] = -186.75 J/K

5 0
2 years ago
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