The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Step-by-step explanation:
4. y=-6/3x+3 (if you can simplify put y=-2x+3)
5. y=5/2x+1
6. y=-8/2x -5 (if you can simplify put y=-4x-5)
7. y=-6/6x+2 (if you can simplify put y=-x+2)
8. y=4/6x-4 (if you can simplify put y=2/3x-4)
9. y=6/5x+0
hope this helped!!!
Answer: b^3+ 64b^2 - b/16 -4
Step-by-step explanation: